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disa [49]
3 years ago
13

The Princess cruise ship left San Francisco and traveled south for 8 hours at a speed of 30mph. What is the velocity of the ship

? Round your answer to the hundreths place
Chemistry
1 answer:
ipn [44]3 years ago
8 0

Answer:

v = 300 mph due South.

Explanation:

Given that,

The Princess cruise ship left San Francisco and traveled south for 8 hours at a speed of 30mph.

We need to find the velocity of the ship. It can be calculated by total distance divided by total time taken.

Velocity is a vector quantity i.e. it has both magnitude and direction. On the other hand, the speed has only magnitude (scalar quantity).

In this case it is mentioned that the cruise is travelling south with a speed of 300 mph.

Hence, the velocity is 300 mph in South direction.

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gA scientist is trying to discover information about an unknown metal in a compound. The formula for the compound is believed to
Hitman42 [59]

Solution :

It is given that :

The formula of the compound = $XBr_3$

And that 4.70 g of the sample contains $4.834 \times 10^{-2}$ mol of Br.

It means that :

1 mol of $XBr_3$ contains = 3 mol of Br

∴ 3 mol of $Br^-$ contain in 1 mol of $XBr_3$

$4.834 \times 10^{-2}$ mol of $Br^-$  contains $1.576 \times 10^{-2}$ mol of $XBr_3$

Thus the mol of $XBr_3$ = $1.576 \times 10^{-2}$ mol

The given mass is = 4.700 g

Therefore, the $\text{molar mass}$ of $XBr_3$  $=\frac{\text{mass}}{\text{mol}}$

                                                           $=\frac{4.700 \ g}{1.576 \times 10^{-2} \ mol}$

                                                          = 298.4 g/mol

So $\text{molar mass}$ of $XBr_3$ = $\text{molar mass}$ of X + 3 x $\text{molar mass}$ of Br

      298.4 g/mol = $\text{molar mass}$ of X + 3 x 79.90 g/mol

      298.4 g/mol = $\text{molar mass}$ of X + 239.7 g/mol

       $\text{molar mass}$ of X = 58.71 g/mol    (since 1 amu = 1 g/mol)      

Therefore the atomic mass of the unknown metal = 58.71 g/mol

So the unknown meta is Nickel.

3 0
3 years ago
How much heat is required to increase the temperature of 20 grams of water by 26 degrees celsius?
mrs_skeptik [129]

Answer: 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.

Explanation:

Given: Mass = 20 g

Change in temperature = 26^{o}C

The standard value of specific heat of water is 4.184 J/ g^{o}C

Formula used to calculate the heat energy is as follows.

q = m \times C \times \Delta T

where,

q = heat energy

m = mass of substance

C = specific heat of substance

\Delta T = change in temperature

Substitute the values into above formula as follows.

q = m \times C \times \Delta T\\= 20 g \times 4.184 J/g ^{o}C \times 26^{o}C\\= 2175.68 J

Thus, we can conclude that 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.

4 0
3 years ago
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