Answer:
-125.4
Explanation:
Target equation is 4C(s) + 5H2(g) = C4H10
These are the data equations for enthalpy of combustion
- C(s) + O2(g) =O2(g) -393.5 kJ/mol * 4
- H2(g) + ½O2(g) =H20(l) = 285.8 kJ/mol * 5
- 2CO2(g) + 3H2O(l) = 13/2O2 (g) + C4H10 - 2877.1 reverse
To get target equation multiply data equation 1 by 4; multiply equation 2 by 5; and reverse equation 3, so...
Calculate 4(-393.5) + 5(-285.8) + 2877.6 and you should get the answer.
Answer:
hello your question is incomplete the options are missing
Determine the resultant velocity for the plane when it is travelling
i) To the east
ii) To the west
answer :i) 270 i
ii) -150 i
Explanation:
velocity of Airplane = 210 m/s
wind velocity = 60 m/s to the east
The resultant velocity for the plane when it is travelling
let the velocity of the wind = V2
velocity of the plane = v1
i) The resultant velocity for the plane when travelling to the east
Vr = V2 i + V1 i
Vr= 60i + 210i = 270i
ii) resultant velocity when the plane is travelling to the west
Vr = - V1 i + V2i
= -210i + 60 i = -150 i
Ammonium hydroxide is basic
