Yes! You are on the right track
The balanced chemical equation would be as follows:
<span>NH3+HCL->NH4CL
For this, we assume these gases are ideal gases so we can use the equation PV=nRT. We first calculate the number of moles of each reactants. We do as follows:
</span>PV=nRT
1.02 (4.21) = n (0.08206)(27+273.15)
n = 0.17 mol NH3 -------><span>consumed completely and therefore the limiting reactant</span>
PV=nRT
0.998 (5.35 L) = n (0.08206)(26+273.15)
n = 0.22 mol HCl
<span>what mass of NH4Cl(s) will be produced?
0.17 mol NH3 (1 mol NH4Cl / 1 mol NH3 ) = 0.17 mol NH3
which gas is the limiting reactant?
NH3 gas
which gas is present in excess?
HCl gas</span>
Answer:
the fuel efficiency in kilometers per liter is 16.561 kilometer per liter
Explanation:
The computation of the full efficiency in kilometers per liter is shown below:
39.0 miles ÷ gallon = (39.0 miles ÷ gallon) × (1.6094 km ÷ 1 miles) × (1 gallon ÷ 3.79 L)
Now cut the opposite miles and gallons
So, the fuel efficiency would be
= 16.561 kilometers per liter
Hence, the fuel efficiency in kilometers per liter is 16.561 kilometer per liter
