Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
<span>To find the answer we must calculate her comission earnings for $45.000 and for the amount she sold above $45.000 (in our case, 51.000 - 45.000 = 6.000). So in total we have 6/100 * 45.000 + 8/100 * 6000 = 2700 + 480 = 3180.</span>
Answer:
1/8
Step-by-step explanation:
.5x.25=.125
1 divided by 8 equals .125
Answer: 2p^2-p
: Quadratic Binomial
Step-by-step explanation:
Your answer should be 253 x 93=22500
