What fraction best represents 5x2/3

Wyatts dog is tethered to a post in his yard. If the rope tied to the dog is 12 feet long, how many sqaure yards does the dog ha

Marrrta [24]

Answer:

AS far the rope let him go Squared

Step-by-step explanation:

7 0

3 years ago

On Monday, Marley rode 8 miles on a bike. On Tuesday, she rode 8 times more than she did Monday. On Wednesday, she rode an addit

12345 [234]

Answer:

The answer is 81!

Step-by-step explanation:

8 x 8 = 64

64 + 8 = 72

72 + 9 = 81

Hope this helped you!

3 0

3 years ago

Is Pamee’s work correct? No, the sequence should be 1, 3, 9, 27, . . . . Yes, Pamee’s work is correct. No, the sequence should b

Anastasy [175]

Answer:this answer is C

Step-by-step explanation:

4 0

3 years ago

An Internet reaction time test asks subjects to click their mouse button as soon as a light flashes on the screen. The light is

Ganezh [65]

Answer:

(a) 0.20

(b) 31%

(c) 2.52 seconds

Step-by-step explanation:

The random variable Y models the amount of time the subject has to wait for the light to flash.

The density curve represents that of an Uniform distribution with parameters a = 1 and b = 5.

So, $Y\sim Unif(1,5)$

(a)

The area under the density curve is always 1.

The length is 5 units.

Compute the height as follows:

$\text{Area under the density curve}=\text{length}\times \text{height}$

$1=5\times\text{height}\\\\\text{height}=\frac{1}{5}\\\\\text{height}=0.20$

Thus, the height of the density curve is 0.20.

(b)

Compute the value of P (Y > 3.75) as follows:

$P(Y>3.75)=\int\limits^{5}_{3.75} {\frac{1}{b-a}} \, dy \\\\=\int\limits^{5}_{3.75} {\frac{1}{5-1}} \, dy\\\\=\frac{1}{4}\times [y]^{5}_{3.75}\\\\=\frac{5-3.75}{4}\\\\=0.3125\\\\\approx 0.31$

Thus, the light will flash more than 3.75 seconds after the subject clicks "Start" 31% of the times.

(c)

Compute the 38th percentile as follows:

$P(Y$

Thus, the 38th percentile is 2.52 seconds.

4 0

3 years ago

Mr. Albano wants to paint menus on the wall of his cafe in chalkboard paint. The gray area below shows where the rectangular men

alex41 [277]

Saw the image.

Given:
Whole wall is 13 2/3 ft by 25ft
4 menus (gray areas) with measurements of 6 ft wide and 7 1/2 ft tall.

Convert mixed fractions into improper fractions.

13 2/3 ft = ((13*3)+2)/3 = 41/3

Area of the Wall = 41/3 ft * 25 ft = (41*25)/3 = 1025/3 ft² = 341 2/3 ft²

7 1/2 ft = ((7*2)+1)/2 = 15/2

Area of the menu = 15/2 ft * 6 ft = (15*6)/2 = 90/2 = 45 ft²
45 ft² x 4 menus = 180 ft²

Area of wall space not covered by the chalkboard paint:
A = 341 2/3 ft² - 180 ft² = 161 2/3 ft²

3 0

3 years ago