Please solve for me it's urgent. A rectangle has 10 and 6cm each. find the area of a square with the same perimeter as that of t
1 answer:
You might be interested in
Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
sq. units.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
Area of KLMN is egual to
Answer:
y = 56
Step-by-step explanation:
the midsegment SV is half the length of the side TU , that is
y - 9 = (y + 38) ← multiply both sides by 2 to clear the fraction
2y - 18 = y + 38 ( subtract y from both sides )
y - 18 = 38 ( add 18 to both sides )
y = 56