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Hatshy [7]
3 years ago
15

Factor x3 ‒ 11x2 ‒ 7x + 77 by grouping. What is the resulting expression?

Mathematics
1 answer:
shepuryov [24]3 years ago
6 0

Answer:

A. (x^{2}-7)\cdot (x-11)

Step-by-step explanation:

The third order polynomial is factored herein:

x^{2}\cdot (x-11) - 7\cdot (x-11)

(x^{2}-7)\cdot (x-11)

Which represents answer A.

You might be interested in
Alvin's age is two times Elga's age. The sum of their ages is 63. What is Elga's age?
lawyer [7]

Answer: Alvin = 42 yrs , Elga = 21 yrs

Step-by-step explanation:

Let Elga's age be x , and Alvin's age be y ,since Alvin is two times Elga's age , then

Alvin's age = 2x , that is

y = 2x ............... equation 1

The sum of their ages is 63 implies

x + y = 63 .............. equation 2

Solving the resulting linear equations by substitution method.

Substitute equation 1 into equation 2 , we have

x + 2x = 63

3x = 63

x = 63/3

x = 21

Therefore : Elga is 21 years old , then Alvin will be 21 x 2, which will be 42

8 0
3 years ago
A regression model involved 18 independent variables and 200 observations. The critical value of t for testing the significance
Evgen [1.6K]

Answer:

The correct answer to the following question will be Option d (181 degrees of freedom).

Step-by-step explanation:

The given values are:

Regression model,

n = 200

Observations,

p = 18

Now,

⇒  n-p-1

On putting the estimated values, we get

⇒  200-18-1

⇒  181

So that the correct choice will be "181 degrees of freedom".

6 0
3 years ago
Please helpp me i need a answer
Lesechka [4]

Answer:

0.0005123

Step-by-step explanation:

The scientific notation 5.123e-4 is same as 5.123×10^-4 or 5.123×10-4. Thus, to get the answer to 5.123e-4 as a decimal, we multiply 5.123 by 10 to the power of -4.

= 5.123e-4

= 5.123 × 10-4

= 0.0005123

7 0
2 years ago
You are standing next to a really big circular lake. You want to measure the diameter of the lake, but you don't
blagie [28]
The diameter is about 1,275.4 because D=C/pi so 4007\pi=1275.4
8 0
3 years ago
PLEASE HELP GUYS i am struggling so much, two questions
ankoles [38]

Answer: the equation of the standard parabola

1) (y-6)^2 = 4 (x-1)

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

<u>Explanation </u>

<u>Parabola:-</u>

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

  • The locus of P such that \frac{SP}{PM} = constant
  • The fixed point  'S' is called the Focus.
  • The fixed line'l 'is called the directrix of the conic
  • The constant ratio is known as the eccentricity, denoted by 'e'
  • If e=1 , the conic is called a parabola

1) <u> Step 1</u> :-

Given the focus   S = (2,6) and directrix is x=0

we know that \frac{SP}{PM}=1

now cross multiplication , we get

SP = PM

squaring on both sides,we get

SP^{2} = PM^2

step 2:-

now using distance formula is

  • \sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)

Given S =(2,6) and P(x,y) be any point on parabola

SP^2 = (x-2)^2+(y-6)^2........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

  • \frac{ax_{1}+by_{1}+c   }{\sqrt{a^2+b^2} }

Given the directrix is x =0 and P(x,y) be any point on parabola

PM^2 = \frac{x^2}{\sqrt{1}^2 }......(2)

equating equation(1) and equation (2), on simplification

we get (x-2)^2+(y-6)^2 = x^2.....(3)

  • apply (a-b)^2 = a^2+  b^2+2 ab

now the equation (3) is

(y-6)^2 = 4 x-4

now the standard form of parabola is

(y-k)^2 = 4 a(x-h)

<u>Final answer</u>:-

(y-6)^2 = 4 (x-1)

2) <u> Explanation:-</u>

<u>step 1:</u>

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

  • Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

(x-h)^2 = 4 a (y-k)

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of AS = \sqrt{(-5-(-5)^2+(2-6)^2}

 on simplification we get a =4

<u>Final answe</u>r :-

the vertex (h,k) = (-5,2) and a=4

(x-h)^2 = 4 a (y-k)

The standard parabola is (x+5)^2 = 16 (y-2)

5 0
3 years ago
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