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Colt1911 [192]
3 years ago
7

Help w this pls it would save me Pleasereeee

Mathematics
1 answer:
elena55 [62]3 years ago
5 0

Answer:

0.6 over 0.6. Or just 1.

Step-by-step explanation:

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The preimeter of the rectangle is 154 feet.The length of the rectangle is 55 feet.What is the width of the rectangle.
Alja [10]

Answer:

22

Step-by-step explanation:

The preimeter is adding all sides together. I took 154-55 twice sense we have four sides of a rectangle and two are lengths. after that i got 44. I then just remembered we had two sides left so divided that by 2 and got 22

7 0
3 years ago
Find the unit rate with the second given unit in the denominator.
Nookie1986 [14]
The answer should be 6/1 or 6.
I hope this helps.
YOU'RE WELCOME :D
8 0
3 years ago
I need help asap!!!​
valentina_108 [34]
The answer is (7,6)

This is because a midpoint is in the exact middle, meaning that both sides are an equal distance away. You can find this by fining the difference between the two corresponding coordinates then adding that difference to the midpoint and that will give you your other endpoint.

Hope this helped !!
7 0
3 years ago
What is that symbol equal to?<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="TexFormula1" title=" \pi " alt=" \pi " align="ab
saveliy_v [14]
3.0l5.516.3282.0.4675.11.8.0.0.0.0.647.647.5-1.1.0
7 0
3 years ago
Read 2 more answers
Marine biologists have been studying the effects of acidification of the oceans on weights of male baluga whales in the Arctic O
PSYCHO15rus [73]

Answer:

c. 61.25 kg

Step-by-step explanation:

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.

a. 15.31 kg

b. 51.40 kg

c. 61.25 kg

d. 80.49 kg

Margin of Error Formula= z × Standard deviation/√n

95% confidence interval = 1.96

Standard deviation = 125kg

n = 16 samples

Margin of error= 1.96 × 125/√16

= 1.96 × 125/4

= 245/4

= 61.25kg

The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg

6 0
3 years ago
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