23. Kim and Jay leave at the same time to travel 25 miles going to the beach.
Kim drives 9 miles in 12 minutes
Jay drives 10 miles in 15 minutes.
Question: who will arrive first?
Unit rate of Kim
=> 9 miles in 12 minutes
=> 0.75 miles / minutes
=> 25 / 0.75
It will take 33.33 minutes for Kim to arrive
Unit rate of Jay
10 miles in 15 minutes.
=> 10 miles /15 minutes
=> 0.67 miles /minute
=> 25 / 0.67
It will take Jay 37.31 minutes to arrive at the beach.
SO Kim will arrive first
3. Three and four tenths. 3+0.4=3.4
4. Two and fifty-one hundredths. 2+0.51=2.51
5. 8/10
6. 0.05
7. 46/100
8. 0.6
9. 9/10
10. 0.35
1 and 2 are correct btw
Hello,
r=5(1+cos t)
r'=5(-sin t)
r²+r'²= 25[(1+cos t)²+(-sin t)²]=50(1-cos t)=50 sin² (t/2)
Between 0 and π, sin x>0 ==>|sin x|=sin x
![l= 2*5* \int\limits^{\pi}_0{sin( \frac{t}{2} )} \, dt= 5[-cos (t/2)]_0^{\pi}\\\\ =5(0+1)=5](https://tex.z-dn.net/?f=l%3D%202%2A5%2A%20%5Cint%5Climits%5E%7B%5Cpi%7D_0%7Bsin%28%20%5Cfrac%7Bt%7D%7B2%7D%20%29%7D%20%5C%2C%20dt%3D%205%5B-cos%20%28t%2F2%29%5D_0%5E%7B%5Cpi%7D%5C%5C%5C%5C%0A%3D5%280%2B1%29%3D5)
Here is the method but i may have make some mistakes.