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AnnZ [28]
3 years ago
5

Bret wants to plot a graph to show the prices of different numbers of skateboards. He has to plot the following points:

Mathematics
1 answer:
Rudik [331]3 years ago
7 0
From 0 to 200 at intervals of 50

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A special discount was offered to the employees of Ryan's, a lead ing men's store. Employees were given their employee discount
Helen [10]

Answer: a) $2155, b) $1763.03.

Step-by-step explanation:

Since we have given that

Number of cable knit sweaters = 15

Cost per sweaters = $65.00

Number of pairs of khaki twill pants = 22

Cost of each pair = $50.00

Number of casual jackets = 18

Cost of each jackets = $62.00

total sale volume would be

15\times 65+22\times 50+18\times 62\\\\=\$3191

Employee discount = 35%

Additional discount = 15%

So, Total markdown dollars taken is given by

3191\times \dfrac{100-35}{100}\times \dfrac{100-15}{100}\\\\=3191\times \dfrac{65}{100}\times \dfrac{85}{100}\\\\=3191\times 0.65\times 0.85\\\\=\$1763.0275

Hence, a) $2155, b) $1763.03.

4 0
3 years ago
Max has been offered positions by two car companies. The first company pays a salary of $12,500 plus commission of $1500 for eac
adell [148]

Answer:

5 Cars

Step-by-step explanation:

Let the number of cars to be sold to make the total pay equal be x.

The first company pays a salary of $12,500 plus commission of $1500 for each car sold.

  • Algebraically written as: 12500+1500x

The second company pays a salary of $17,500 plus a commission of $500 per car sold.

  • Algebraically written as: 17500+500x

Equating both sides

12500+1500x=17500+500x

Collect like terms

1500x-500x=17500-12500

1000x=5000

Divide both sides by 1000

x=5

Therefore, when 5 cars are sold, the total pay would be the same.

7 0
3 years ago
Please Please Please help with this math problem
katovenus [111]
  1. The revenue as a function of x is equal to -x²/20 + 920x.
  2. The profit as a function of x is equal to -x²/20 + 840x - 6000.
  3. The value of x which maximizes profit is 8,400 and the maximum profit is $3,522,000.
  4. The price to be charged to maximize profit is $500.

<h3>How to express the revenue as a function of x?</h3>

Based on the information provided, the cost function, C(x) is given by 80x + 6000 while the demand function, P(x) is given by -1/20(x) + 920.

Mathematically, the revenue can be calculated by using the following expression:

R(x) = x × P(x)

Revenue, R(x) = x(-1/20(x) + 920)

Revenue, R(x) = x(-x/20 + 920)

Revenue, R(x) = -x²/20 + 920x.

Expressing the profit as a function of x, we have:

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = -x²/20 + 920x - (80x + 6000)

P(x) = -x²/20 + 840x - 6000.

For the value of x which maximizes profit, we would differentiate the profit function with respect to x:

P(x) = -x²/20 + 840x - 6000

P'(x) = -x/10 + 840

x/10 = 840

x = 840 × 10

x = 8,400.

For the maximum profit, we have:

P(x) = -x²/20 + 840x - 6000

P(8400) = -(8400)²/20 + 840(8400) - 6000

P(8400) = -3,528,000 + 7,056,000 - 6000

P(8400) = $3,522,000.

Lastly, we would calculate the price to be charged in order to maximize profit is given by:

P(x) = -1/20(x) + 920

P(x) = -1/20(8400) + 920

P(x) = -420 + 920

P(x) = $500.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

3 0
2 years ago
Special right triangles​
uysha [10]

Answer:

i dont think I can help I am really sorry

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Find the absolute value of complex number Z = 2+5
sasho [114]
The answer would be 7.
6 0
3 years ago
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