All categories

3 years ago

The area of a rectangle is w^2+4w=60 where w is the width. find the width.

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

6 0

The width of rectangle is 6.

Step-by-step explanation:

Given,

Area of rectangle; w²+4w=60

As w is the width, we will solve the equation to find w.

$w^2+4w=60$

Subtracting 60 from both sides

$w^2+4w-60=0$

Factorizing the equation;

$w^2+10w-6w-60=0\\w(w+10)-6(w+10)=0\\(w+10)(w-6)=0$

Either,

w+10=0 => w=-10

Or,

w-6=0 =>w=6

As width cannot be negative, therefore

Width = 6

The width of rectangle is 6.

Keywords: area, rectangle

Learn more about area at:

#LearnwithBrainly

You might be interested in

Sketch a quadratic function with the given characteristics.

xeze [42]

Answer:

See photo below

Add arrows to the two ends of the parabola.

Step-by-step explanation:

To sketch this quadratic function, we to connect three dots: the two roots and a vertex.

The given roots are -1 and 1.

Draw two dots at the x-intercepts, which are (-1, 0) and (1, 0).

Vertex dot: V (x, y)

The vertex x-coordinate always in the middle of the two roots. The middle of -1 and 1 is 0. That's the same as the y-axis.

V (0, y)

Since the function increases when x < 0, the parabola will open up.

We read from left to right. The greater numbers are towards the top of the page.

You can put the vertex anywhere on the y-axis that is below the x-axis.

7 0

3 years ago

Beth works as a sales rep and receives $43 for every $210 she sells. What is her rate of commission? Round to the nearest tenths

Soloha48 [4]

Answer: it should be 5 if im not mistaken

Step-by-step explanation:

6 0

3 years ago

Find the discriminant and determine the nature of the roots to the quadratic equation

Katen [24]

№17
$x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2} \\ \\ x_{1} = \frac{-6+8}{2} =1 \\ \\ x_{2} = \frac{-6-8}{2} =-7$
Answer: x₁ = 1
   x₂ = - 7

№18
$2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\ \\ D= -3 ^{2} -4*2=9-8=1 \\ \\ x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\ \\ x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5$
Answer: x₁ = 1
     x₂ = 0,5.

№19
$2 x^{2} -4x-5=0 \\ D=-4 ^{2} -4*2*(-5)=16+40=56 \\ \\ x_{1}= \frac{4+ \sqrt{56} }{2*2} = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5} \\ \\ x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} - \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 
$
Answer: x₁ = 1 + √3.5
     x₂ = 1 - √3.5

3 0

3 years ago

Need help nadding and subtracting functions

SCORPION-xisa [38]

Answer:

2x² + $\frac{3}{2}$ x - 5

Step-by-step explanation:

(f + g)(x) = f(x) + g(x), thus

f(x) + g(x)

= $\frac{x}{2}$ - 2 + 2x² + x - 3 ← collect like terms

= 2x² + $\frac{3}{2}$ x - 5

3 0

3 years ago

How can you use the sign of the points to determine location? please help and i will give brainliest :D

Vladimir [108]

To determine the location of a point on a graph, the first number of the ordered pair is a x-coordinate which means the first number you would look for would be the horizontal line, or the x-axis. The second number is the y-coordinate which means that you would look on the vertical line, or the y-axis. You would go on the horizontal line first, then from there go up to the y-coordinate and place your point. (I'm sorry if it's long but you can try to shorten it.)

Hope this helped!

Have a nice day!

8 0

3 years ago