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GalinKa [24]
2 years ago
8

Jannie bring 100 bags of candy to sell at the school fair. Each bag weighs 1lb and she plans to sell each for 66 cents. Jannie f

ills the bags with 40 lb of sugar candies worth 75 cents a pound, and some jelly beans. How much does 1 pound of jelly beans cost?
Mathematics
2 answers:
Art [367]2 years ago
5 0

Answer:

60 cents

Step-by-step explanation:

;)

postnew [5]2 years ago
4 0

Answer:

60 cents

Step-by-step explanation:

The equation will be: the 40lb sugar candies worth 75 cents a pound added to 60lb (100-40) jelly beans worth x cents = 100 pounds worth 66 cents a pound

(.75 times 40)+(x times 60)= .66 times 100

30+60x=66

60x=36

x=.6

Meaning 60 cents

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Step-by-step explanation:

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Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4
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Answer:

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Step-by-step explanation:

We need to simplify the expression (6^{-2})(3^{-3})(3*6)^4

Solving:

(6^{-2})(3^{-3})(3*6)^4

Applying exponent rule: a^{-m}=\frac{1}{a^m}

=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\

Factors of 18=2\times 3\times 3=2\times3^2

Factors of 6=2\times 3

Replacing terms with factors

=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\

Using exponent rule: (a^m)^n=a^{m\times n}

=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}

Using exponent rule: a^m.a^n=a^{m+n}

=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}

Now using exponent rule: \frac{a^m}{a^n}=a^{m-n}

=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108

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7 0
3 years ago
Need help on this ASAP
serg [7]

Answer:

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