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gavmur [86]
2 years ago
8

oe and Ted are both running laps. Joe is running at 10 minutes per lap, and Ted is running at 12 minutes per lap. A photographer

wants to take a picture of them as they finish a lap at the same time. How many minutes will the photographer have to wait?
Mathematics
2 answers:
galben [10]2 years ago
5 0
As long as both of them start the race at the same time the photographer will have to wait for 12 min
kow [346]2 years ago
3 0
Maybe 22 minutes if you have to add them together
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Which method correctly solves the equation using the multiplication property of equality and the reciprocal of one-third? one-th
Marianna [84]

The solution to the equation one-third (x + 9) = negative 12 is  x = -45

<h3>How to solve the equation?</h3>

The equation is given as:

one-third (x + 9) = negative 12

Rewrite properly as:

1/3 (x + 9) = -12

Multiply both sides by 3

x + 9 = -36

Subtract 9 from both sides

x = -45

Hence, the solution to the equation one-third (x + 9) = negative 12 is  x = -45

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Andrej [43]

Answer:

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Step-by-step explanation:

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Lou runs 4 miles each day for 5 days a week. If he does this for 7 weeks, how
Shkiper50 [21]

Answer:

140 miles

Step-by-step explanation:

4 per day for 5 days a week

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X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
2 and 2 over 2, divided by -1/4 = what
alex41 [277]

Answer:

1.75

Step-by-step explanation:

it is right

6 0
3 years ago
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