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gavmur [86]
3 years ago
8

oe and Ted are both running laps. Joe is running at 10 minutes per lap, and Ted is running at 12 minutes per lap. A photographer

wants to take a picture of them as they finish a lap at the same time. How many minutes will the photographer have to wait?
Mathematics
2 answers:
galben [10]3 years ago
5 0
As long as both of them start the race at the same time the photographer will have to wait for 12 min
kow [346]3 years ago
3 0
Maybe 22 minutes if you have to add them together
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(x-1)(x-3)(x+5)(x+7)=297
mihalych1998 [28]

First simplify the expression into polynomial form,

(x-1)(x-3)(x+5)(x+7)=297

x^4+8x^3-10x^2-104x+105=297

x^4+8x^3-10x^2-104x-192=0

Now factor into,

(x-4)(x+8)(x^2+4x+6)=0

Which means the solutions are,

x-4=0\implies\boxed{x_1=4}

x+8=0\implies\boxed{x_2=-8}

and then two complex solutions because determinant of the third factor D\lt0,

x^2+4x+6=0

x^2+4x+4=-2

(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}

Hope this helps :)

5 0
3 years ago
Read 2 more answers
13) Based on her results, what is the experimental probability of landing on a blue section?
AveGali [126]
I believe that it would be a-21/49
6 0
3 years ago
What type of proof is used extensively in Geometry?
Nikolay [14]

Answer: two-column

Step-by-step explanation:

7 0
3 years ago
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Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. use the
mamaluj [8]

A binomial distribution is an experiment where there are two outcomes; Success and failure. For instance, you are given n = 128 and p = 0.27. The formula for the variance of a binomial distribution is n*p(1 – p) or n*p*q*. They are equivalent because q = 1- p. We will use the first equation.

 

Variance = n*p*(1 – p)

Variance = 128*0.27*(1 – 0.27)

Variance = 25.23

 

To get the standard deviation, find the square root of the variance.

Standard deviation = sqrt (Variance)

Standard deviation = sqrt (25.23)

<span>Standard deviation = 5.02</span>

7 0
3 years ago
Which long division problem can be used to prove the formula for factoring the difference of two perfect cubes?
Stells [14]

Answer:

<h2>a³-b³  = (a-b)(a²+ab+b²)</h2>

Step-by-step explanation:

let the two perfect cubes be a³ and b³. Factring the  difference of these two perfect cubes we have;

a³ - b³

First we need to factorize (a-b)³

(a-b)³ = (a-b) (a-b)²

(a-b)³ = (a-b)(a²-2ab+b²)

(a-b)³ = a³-2a²b+ab²-a²b+2ab²-b³

(a-b)³ = a³-b³-2a²b-a²b+ab²+2ab²

(a-b)³ = a³-b³ - 3a²b+3ab²

(a-b)³  = (a³-b³) -3ab(a-b)

Then we will make a³-b³ the subject of the formula from the resultinh equation;

a³-b³ =  (a-b)³+ 3ab(a-b)

a³-b³  = a-b{(a-b)²+3ab}

a³-b³  = a-b{a²+b²-2ab+3ab}

a³-b³  = (a-b)(a²+b²+ab)

a³-b³  = (a-b)(a²+ab+b²)

The long division problem that can be used is (a-b)(a²+ab+b²)

3 0
3 years ago
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