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Nataly [62]
3 years ago
8

A circle that has a center at the point (3, -2) with a radius of 6. Write an equation for the circle.

Mathematics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

(x – 3)^2+ (y +2)^2 = 36

Step-by-step explanation:

Given data

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r^2,

where (h, k) represents the coordinates of the center of the circle

h=3

k=-2

r= 6

Substitute

(x – 3)^2+ (y – (-2))^2 = 6^2

(x – 3)^2+ (y +2)^2 = 36

Hence the expression for the equation of the circle is

(x – 3)^2+ (y +2)^2 = 36

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Quadratic equations are second-order equations. Ginney made a mistake when she identified b = 31. It should be b = –31.

<h3>What is a Quadratic Equation?</h3>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

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In order to find the mistake that Ginny made, we will first find the factors ourselves, therefore, we will factorize the trinomial,

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As we can see that the value of constants are,

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6x^2 - 31x -30 = 0\\\\6x^2 - 36x+5x -30 = 0\\\\6x(x-6)+5(x-6)=0\\\\(6x+5)(x-6)=0

Therefore, the factors of the trinomial 6x^2 - 31x -30 = 0 are (6x+5) and (x-6).

If we compare our process with Ginny's process, we will find that she has taken the value of the constant b as 31 which is wrong.

Hence, Ginney made a mistake when she identified b = 31. It should be b = –31.

Learn more about Quadratic Equation:

brainly.com/question/17177510

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