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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
-circumference is equal to pi×diameter, area is equal to pi×radius^2
-28.26÷3.14=9, 9÷2=4.5, 4.5×4.5=20.25, and 20.25×3.14=63.585
-rounded to the nearest hundredth, the answer is 63.59
Answer:
$ 746.16
Step-by-step explanation:
MONTHLY interest = .0335/4
4 years = 48 months
500 ( 1 + .0335/4)^48 = 746.16
Your answer would be 45,because 6 times 45 equals to 470,and thats how many times 6 can go into 470,exactly 45 times
