If M is the midpoint of JK then JM+MK=JK and JM=MK
so
6x-7=2x+3
minus 2x both sides
4x-7=3
add 7 both sides
4x=10
divide both sides by 4


sub back
JM=6x-7



JM=8
JM=MK=8
JM+MK=8+8=16=JK

and JM=8=MK and JK=16
<h3>
Answer: True</h3>
Explanation:
The area of the circle with radius 10 is...
A = pi*r^2
A = pi*10^2
A = 100pi
The surface area of the sphere with radius 5 is...
SA = 4pi*r^2
SA = 4pi*5^2
SA = 100pi
Both results are the same, so the claim is true. We can think of surface area as the amount of wrapping paper needed to cover the sphere.
circumference of the mirror = 175.84 cm
area of the mirror = 2461.76 cm²
The measure needed to find the amount of wire round the mirror is the circumference.
The measure needed to find the amount of glass needed is the area.
<h3>How to find area and circumference of a circle?</h3>
The circumference and area of a circle can be found as follows:
circumference of the mirror = 2πr
circumference of the mirror = 2 × 3.14 × 28 = 175.84 cm
area of the mirror = πr²
area of the mirror = 3.14 × 28²
area of the mirror = 2461.76 cm²
The measure needed to find the amount of wire round the mirror is the circumference.
The measure needed to find the amount of glass needed is the area.
learn more on circle here: brainly.com/question/16125353
#SPJ1
Answer:radius = diameter/2=12/2=6cm...
area of semicircle = πr^2/2
={3.14×(2)^2}/2
=6.28cm^2.......
Step-by-step explanation:
Answer:
399/1234
Step-by-step explanation:
The relative frequency is the fraction (ratio) of sophomores to total students.
There are 399 sophomores, and 1234 total students.
So, the relative frequency is 399/1234