How many moles are .20 Grams silver sulfate
1 answer:
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Answer:
The absolute uncertainty is approximately 1.69 × 10⁻³
Explanation:
The volume needed for NaOH needed to make the solution = 16.66 ml
The wt% of the added NaOH = 53.4 wt%
The volume of the NaOH to be prepared = 2.00 L
The concentration of the NaOH to be prepared = 0.169 M
The molar mass of NaOH = 39.997 g/mol
Therefore, 100 g of sample contains 53.4 g of NaOH
The mass of the sample = 16.66 × 1.52 = 25.3232 g
The mass of NaOH in the sample = 0.534 × 25.3232 = 13.5225888 g ≈ 13.52 g
Therefore;
The number of moles of NaOH = 13.52/39.9971 = 0.3381 moles
Therefore, we have 0.3381 moles in 2.00L solution, which gives;
The number of moles per liter = 0.3881/2 = 0.169045 moles/liter
The molarity ≈ 0.169 M
The absolute uncertainty, u(c) is given as follows;
The absolute uncertainty, u(c) ≈ 1.69 × 10⁻³.
Answer:
2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.
Explanation:
Moles of NaOH =
Molarity of the nitric acid solution = 0.250 M
Volume of the nitric solution = 0.150 L
Moles of nitric acid = n
According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :
of NaOH
Moles of NaOH left unreacted in the solution =
= 0.375 mol - 0.0375 mol = 0.3375 mol
1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.
Then 0.3375 moles of NaOH will give :
of hydroxide ion
The molarity of hydroxide ion in solution ;
2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.