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2 years ago

The formation of iodine is described by the following chemical equation:

Chemistry

1 answer:

olga nikolaevna [1]2 years ago

7 0

Answer:

N2O2(g) +O2(g) ===> 2NO2(g)

Explanation:

For a nonelementary reaction, the reaction equation is described as the sum of all the steps involved. All these steps constitute the reaction mechanism. Each step in the mechanism is an elementary reaction. The rate law of the overall reaction involves the rate determining step (slowest step) in the reaction sequence.

Now look at the overall reaction 2NO(g) + O2(g) ---------> 2NO2(g)

The two steps in the mechanism are

2NO(g) --------->N2O2(g) (fast)

N2O2(g) +O2(g) -------> 2NO2(g) (slow)

Summing all the steps and cancelling out the intermediate N2O2(g), we obtain the reaction equation;

2NO(g) + O2(g) ---------> 2NO2(g)

Hence the answer.

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what are the differences between the double displacement reaction and the displacement reaction ? explain with a chemical equati

guajiro [1.7K]

In a displacement reaction, a more reactive element replaces a less reactive element from a compound. In a double displacement reaction, two atoms or a group of atoms switch places to form new compounds.

Explaination:

Displacement chemical reaction :

A displacement reaction is the one wherein the atom or a set of atoms is displaced by another atom in a molecule. For instance, when iron is added to a copper sulphate solution, it displaces the copper metal.

Fe + CuSO4 → FeSO4 + Cu. When zinc is added to a copper sulphate solution, it displaces the copper metal. ...

Zn + CuSO4 → ZnSO4 + Cu.

etc.

Double Displacement Chemical Reaction :

Double displacement reactions take place mostly in aqueous solutions wherein the ions precipitate and exchange of ions takes place. For example, when a solution of barium chloride is mixed with sodium sulphate, a white precipitate of barium sulphate is formed rapidly. These reactions are ionic in nature.

Here are some examples of double displacement reaction: AgNO 3 + NaCl → AgCl + NaNO.

2NaCl + CaSO4 → Na2SO4+ CaCl.

H2SO4 + 2LiOH ⇌ Li2SO4 + 2H2O.

8 0

1 year ago

Which of the compounds in the table below is listed in the wrong colum?

Sveta_85 [38]

Answer: C

Explanation: This is because of a nice thing called guessing

5 0

2 years ago

A piece of metal with a mass of 17.1 g was dropped into a graduated cylinder containing 17.00 mL of water. The graduated cylinde

Mademuasel [1]

The density of the metal with a mass of 1.71g that was dropped into a graduated cylinder containing 17.00 mL of water is 1.005g/mL.

<h3>How to calculate density?</h3>

The density of a substance can be calculated by dividing the mass of the substance by its volume. That is;

Density = mass ÷ volume

According to this question, a piece of metal with a mass of 17.1 g was dropped into a graduated cylinder containing 17.00 mL of water. The density can be calculated as follows:

Density = 17.1g ÷ 17.00mL

Density = 1.005g/mL

Therefore, the density of the metal with a mass of 1.71g that was dropped into a graduated cylinder containing 17.00 mL of water is 1.005g/mL.

Learn more about density at: brainly.com/question/15164682

#SPJ1

6 0

11 months ago

Give the name of the following molecule

shutvik [7]

Answer:

$\boxed{Heptene}$

Explanation:

Double Bond => An Alkene molecule

So, the suffix will be "-ene"

7 Carbons => So, we'll use the prefix "Hept-"

Combining the suffix and prefix, we get:

=> Heptene

7 0

3 years ago

Read 2 more answers

if 1.386 g of mg ribbon combusts to form 2.309 g of oxide product, calculate the experimental mass percent of oxygen from this d

Pavlova-9 [17]

1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.

Let's consider the reaction for the combustion of Mg.

Mg + 1/2 O₂ ⇒ MgO

1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:

$mMgO = mMg + mO\\mO = mMgO - mMg = 2.309 g - 1.386 g = 0.923 g$

We can calculate the mass percent of O in MgO using the following expression.

$\% O = \frac{mO}{mMgO} \times 100\% = \frac{0.923 g}{2.309g} \times 100\% = 40.0 \%$

You can learn more about mass percent here: brainly.com/question/14990953

3 0

1 year ago