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atroni [7]
2 years ago
7

Theater A charges $5 for tickets and $2 per snack that is bought. Theater B

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
8 0

Answer:

the answer is d.

Step-by-step explanation:

as soon as you go to the theater, you HAVE to pay $5 in theater a, with two dollars for ONE snack bought, and it says two dollars PER one snack bought. therefore if x was 2, so if someone wanted to buy 2 snacks, then you would multiply by 2 to get the total cost, or y, for the snacks. answer d is the only one that has the correct numbers in the correct places for theater a and b.

hope this helps!

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On which triangle can the law of cosines be applied once to find an unknown angle measure? Law of cosines: a2 = b2 + c2 – 2bccos
Maksim231197 [3]

Answer:

C) Angle X Y W is 76 degrees. The length of X Y is 5, the length of W Y is 10, and the length of W X is y.

Step-by-step explanation:

On which triangle can the law of cosines be applied once to find an unknown angle measure?

The Law of cosines is given as:

a² = b² + c² - 2bccos(A)

From the options given above, the correct option is Option C

C) Angle X Y W is 76 degrees. The length of X Y is 5, the length of W Y is 10, and the length of W X is y.

This is because:

Law of Cosines helps us to find an unknown side of a triangle when we are given 2 known sides and 1 angle.

In the above question, we are given angle 76 degree, and the length of two sides: The length of X Y is 5, the length of W Y is 10

The unknown side is the length of W X which is represented as y.

Hence, Option C is the correct option.

3 0
3 years ago
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Arte-miy333 [17]

Answer:

3)  m = 18  

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Step-by-step explanation:

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If 5 is subtracted from the square of a number ,the result is 4 , find the number.
Levart [38]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
How many ml of a 20% acid mixture and a 80% acid mixture should be mixed to get 120ml of a 35% acid mixture?
shutvik [7]

Answer:

Volume of Mixture A =90 ml

Volume of Mixture B =30 ml

Step-by-step explanation:

Let say, Mixture A + Mixture B = Mixture C

Volume of Mixture A is x

Volume of Mixture B is y

So, Volume of Mixture C is x+y = 120 ml

Now, Acid contain in Mixture A is 20% =0.2x

Acid contain in Mixture B is 80% =0.8y

Also, Acid contain in Mixture C is 35% =(0.35)(x+y) = 0.35×120=42

Now, we know that,

Acid contain of Mixture A + Acid contain of Mixture B=Acid contain of Mixture C

∴ 0.2x+0.8y=42

∴ 2x+8y=420

We get two linear equations

2x+8y=420 and x+y = 120

Solving above equation...

∴ x=120-y

Replacing x value in 2x+8y=420

∴ 2(120-y)+8y=420

∴ 240-2y+8y=420

∴ 6y=180

∴ y=30

Replacing y value in any equation

∴ x=120-y=120-30=90

∴ x=90

Thus,

Volume of Mixture A is x=90 ml

Volume of Mixture B is y=30 ml

3 0
3 years ago
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