PLEASE HELP FAST! I’ll give brainlist and extra points for right answer

Assume Earth and a cloud layer 770 m above the Earth can be treated as plates of a parallel-plate capacitor.

Travka [436]

Answer:

(a) 1.15×10⁻⁸ F.

(b) 1.5×10⁻⁸ C.

Step-by-step explanation:

(a)

Capacitance of a capacitor: This is the ability for a capacitor to store charge.

The S.I unit of capacitance of a capacitor is Farad (F).

Mathematically, it is represented as

C = ε₀A/d² ................. Equation 1

Where C = Capacitance of the capacitor, ε₀ = permitivity of free space, A = area of the plates, d = distance between the plates.

Given: A = 1×10⁶ m². d = 770 m

Constant: ε₀ = 8.85×10⁻¹² F/m

Substituting these values into equation 1

C = 8.85×10⁻¹²(1×10⁶ )/770

C = 8.85×10⁻⁶/770

C= 0.0115×10⁻⁶

C = 1.15×10⁻⁸ F.

Thus the capacitance of the cloud layer = 1.15×10⁻⁸ F.

(b)

Electric Field Strength: This is the force per unit charge which is exerted at a point in a in a electric field.

It can be represented mathematically as

E = kq/d²........................... Equation 2

Where E = Electric Field Strength, q = charge, d = distance. k = proportionality constant.

Making q the subject of the equation above,

q = Ed²/k ........................... Equation 3.

Given: E = 2×10⁶ N/C, d = 770 m

Constant: k = 1/4πε₀ = 9×10⁹ Nm²/C²

Substituting these values into equation 3

q = 2×10⁶(770)²/(9×10⁹)

q = (2×10⁶)(592900)/(81×10¹⁸)

q = 14639.5×10⁻¹²

q ≈ 1.5×10⁻⁸ C.

Thus the charge the cloud can hold = 1.5×10⁻⁸ C.

3 0

4 years ago

To net an owner $900000 after paying a 6% commission, the list price would be

ch4aika [34]

The list price after commission would be $954,000.

6 0

4 years ago

Simplify: (8t4 + 6 )+(914 – 2ť + 6t? – 6 )

vekshin1

Answer:t

2⋅(17t 2 −2t+6)

Step-by-step explanation:

v(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

2

:

Equation at the end of step

2

:

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

3

:

Equation at the end of step

3

:

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

4

:

Equation at the end of step

4

:

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

2

:

Equation at the end of step

2

:

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

3

:

Equation at the end of step

3

:

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

4

:

Equation at the end of step

4

:

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

(8•(t4))+6)+((((9•(t4))-(2•(t3)))+(2•3t2))-6)

STEP

2

:

Equation at the end of step

2

:

((8•(t4))+6)+((((9•(t4))-2t3)+(2•3t2))-6)

STEP

3

:

Equation at the end of step

3

:

((8•(t4))+6)+(((32t4-2t3)+(2•3t2))-6)

STEP

4

:

Equation at the end of step

4

:

(23t4 + 6) + (9t4 - 2t3 + 6t2 - 6)

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

17t4 - 2t3 + 6t2 = t2 • (17t2 - 2t + 6)

5 0

3 years ago

Find the slope of the line described by 3y = x + 6.

Alexxx [7]

$3y = x +6 \\\\\implies y = \dfrac 13 (x+6)\\\\\implies y = \dfrac 13 x + 2\\\\\text{The above equation is in a form of y = mx +b, where m is the slope.}\\\\\\\text{Hence slope of the line,}~ m= \dfrac 13$

7 0

2 years ago

What is the solution to the equation<br> -3D/

MA_775_DIABLO [31]

Answer:

thats not a question

Step-by-step explanation:

4 0

3 years ago