The median has the property of being equal to 1/2 the length of the 2 parallel lines in a trapezoid. In this case. 1/2 [(x + 8) + (5x + 4)] = 24 There is your equation. Now all you have to do is solve it.
1/2 (x + 8 + 5x + 4) = 24 I've removed the inner brackets.
1/2 (6x + 12) = 24 Gathered like terms.
(6x + 12) = 24*2 Multiplied both sides by 2
6x + 12 = 48 removed the brackets.
6x = 48 - 12 subtracted 12 from both sides.
6x = 36 Divide by 6
x = 36/6
x = 6
6 <<< answer.
We know that
if cos x is positive
and
sin x is negative
so
the angle x belong to the IV quadrant
cos x=5/13
we know that
sin²x+cos²x=1-------> sin²x=1-cos²x------> 1-(5/13)²---> 144/169
sin x=√(144/169)-------> sin x=12/13
but remember that x is on the IV quadrant
so
sin x=-12/13
Part A) <span>cos (x/2)
cos (x/2)=(+/-)</span>√[(1+cos x)/2]
cos (x/2)=(+/-)√[(1+5/13)/2]
cos (x/2)=(+/-)√[(18/13)/2]
cos (x/2)=(+/-)√[36/13]
cos (x/2)=(+/-)6/√13-------> cos (x/2)=(+/-)6√13/13
the angle (x/2) belong to the II quadrant
so
cos (x/2)=-6√√13/13
the answer Part A) is
cos (x/2)=-6√√13/13
Part B) sin (2x)
sin (2x)=2*sin x* cos x------> 2*[-12/13]*[5/13]----> -120/169
the answer Part B) is
sin(2x)=-120/169
The complete question in the attached figure
step 1
find the area of the wall
[area of the wall]=[area of rectangle]+[area of triangle]
[area of the wall]=[3*2]+[3*1/2]----> 7.5 m²
1 m²-------> 10.7639 ft²
area of the wall------> 7.5*10.7639------> 80.73 ft²
we know that
1 can of paint covers an area of --------> 24 ft²
x---------------------------------------------> 80.73 ft²
x=80.73/24---------> x=3.36 can of paints
the answer isT<span>
he fewest number of cans is 4</span>
Answer:
b
Step-by-step explanation:
Each box represents 1/3. 5/3 of white is 2 boxes more so red needs 2 boxes more than white. 5 red and 3 white is the only one that follows the criteria.