Answer:
Solution for 29-(2c+3)=2(c+3)+c equation:
Simplifying
29 + -1(2c + 3) = 2(c + 3) + c
Reorder the terms:
29 + -1(3 + 2c) = 2(c + 3) + c
29 + (3 * -1 + 2c * -1) = 2(c + 3) + c
29 + (-3 + -2c) = 2(c + 3) + c
Combine like terms: 29 + -3 = 26
26 + -2c = 2(c + 3) + c
Reorder the terms:
26 + -2c = 2(3 + c) + c
26 + -2c = (3 * 2 + c * 2) + c
26 + -2c = (6 + 2c) + c
Combine like terms: 2c + c = 3c
26 + -2c = 6 + 3c
Solving
26 + -2c = 6 + 3c
Solving for variable 'c'.
Move all terms containing c to the left, all other terms to the right.
Add '-3c' to each side of the equation.
26 + -2c + -3c = 6 + 3c + -3c
Combine like terms: -2c + -3c = -5c
26 + -5c = 6 + 3c + -3c
Combine like terms: 3c + -3c = 0
26 + -5c = 6 + 0
26 + -5c = 6
Add '-26' to each side of the equation.
26 + -26 + -5c = 6 + -26
Combine like terms: 26 + -26 = 0
0 + -5c = 6 + -26
-5c = 6 + -26
Combine like terms: 6 + -26 = -20
-5c = -20
Divide each side by '-5'.
c = 4
Simplifying
c = 4
