Answer:
90%
Step-by-step explanation:
90%
I hope this helps!
A number that is less that 7.5 can be used as the lesser of the two consecutive integers with the sum greater than 16, but only if the number used was added with one.
Step-by-step explanation:

Answer:
34 minutes
Step-by-step explanation:
Given


Required
Number of minutes left to spend (x)
Since there's only 1 minute left to spend on every other call;
Time left = x * 1
Time left = x
The required can further be calculated using:

This gives:

Subtract 6 from both sides


<em>Hence, there are 34 minutes left to spend</em>