For 100, your answer will be 102; For 898, your answer will be x; 100*x = 102*898 ... 102/x = 100/898 or x/102 = 898/100; x = 898*102/100 = 91596/100 = 915.96.

Hope this helps ∝

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7 0

2 years ago

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The projected world population (in billions of people) t years after

MA_775_DIABLO [31]

Answer:

y = 5 e^r * t

Let y be the population in billions and t the value of elapsed years

7 = 5 e^r * t is the equation being used where t = 15

7/5 = e^r * t

ln 7/5 = r * t taking ln of both sides

r = .336 / 15 = .0224

y = 5 e^(.0224 t) is then our equation

Check - suppose you want y at 2020

y = 5 e^(.0224 * 20) would be the equation

y = 5 e^.449 = 7.83 billion - seems to be a reasonable answer

4 0

2 years ago

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A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach

nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that $\mu = 130, \sigma = 30$