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Nikolay [14]
3 years ago
15

Cara is picking out a shirt. She has a white shirt​, a green shirt​, and a yellow shirt to choose from. Cara is going to pick on

e at random and wants to know what the chance is she will pick a green shirt. Identify the​ action, the sample​ space, and the event.
Mathematics
1 answer:
erastova [34]3 years ago
3 0

Answer:

all the shorts are are identical and only differ in colours so she has an equal chance of picking out any shirt. so she has a 33.3% chance of picking out any shirt.

Step-by-step explanation:

100÷3=33.3'

33.3'% chance for every shirt

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Use the definition of continuity and the properties of limits to show that the function f(x)=x sqrtx/(x-6)^2 is continuous at x
qaws [65]

Answer:

The function is  continuous at  x = 36

Step-by-step explanation:

From the question we are told that

      The  function is f(x)  =  x *  \sqrt{ \frac{x}{ (x-6) ^2 }  }  

       The  point at which continuity is tested is  x =  1

Now from the definition  of continuity ,

   At function is continuous at  k if  only  

       \lim_{x \to k}f(x)  =  f(k)

So

      \lim_{x \to 36}f(x)  =  \lim_{n \to 36}[x *  \sqrt{ \frac{x}{ (x-6) ^2 }  }]

                            = 36 *  \sqrt{ \frac{36}{ (36-6) ^2 }  }

                             = 7.2

Now  

     f(36) = 36  *  \sqrt{ \frac{36}{ (36-6) ^2 }  }

     f(36) = 7.2

So  the given function is continuous at  x =  36

because

          \lim_{x \to 36}f(x)  =  f(36)

7 0
3 years ago
PLZ ASAP help meee I need u nowww
Zepler [3.9K]

<em>Answer</em><em>:</em>

<h2><em>£</em><em> </em><em>1</em><em>4</em><em>1</em><em>6</em><em>8</em></h2>

<em>sol</em><em>ution</em><em>,</em>

<em>Price</em><em> </em><em>of</em><em> </em><em>car</em><em>=</em><em>£</em><em>1</em><em>5</em><em>4</em><em>0</em><em>0</em>

<em>After</em><em> </em><em>reducti</em><em>on</em><em>:</em>

<em>15400 - 15400 \times  \frac{8}{100}  \\  = 15400 - 1232 \\  = 14168</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

5 0
4 years ago
PLEASE HELP!! I NEED THIS TO PASS.
Tanzania [10]
Let's apply the Law of Cosines here.  We want the measure of the angle opposite the side with length 16.

Call that angle C.

Then 16^2 = 36^2 + 28^2 - 2(36)(28)cos C.

Solving for C:  cos C = 16^2 - 36^2 - 28^2 
                                     -------------------------  = 0.904, and C = 0.44 rad
                                         -2(28)(36)                           or  C = 25.21 degrees

So each of the 2 equal angles shown has the measure 25.21 degrees.

Unfortunately, I don't know the direction we should go from this point on.




3 0
3 years ago
Please help me!!!! I don’t understand
ololo11 [35]

Answer:

<h2>m∠EFG = 126°</h2><h2>m∠GFH = 54°</h2>

Step-by-step explanation:

If ∠EFG and ∠GFH are a linear pair, then m∠EFG + m∠GFH = 180°

(look at the picture).

We have

m∠EFG = 5n + 16

m∠GFH = 2n + 10

Substitute:

(5n + 16) + (2n + 10) = 180             <em>combine like terms</em>

(5n + 2n) + (16 + 10) = 180

7n + 26 = 180            <em>subtract 26 from both sides</em>

7n + 26 - 26 = 180 - 26

7n = 154         <em>divide both sides by 7</em>

7n/7 = 154/7

n = 22

Insert the value of n into expressions that specify angle measures:

m∠EFG = 5n + 16 → m∠EFG = 5(22) + 16 = 110 + 16 = 126°

m∠GFH = 2n + 10 → m∠GFH = 2(22) + 10 = 44 + 10 = 54°

8 0
3 years ago
The graph of a linear equation has a slope of -2 and passes through point (-4, 3 ) what is the equation of the line
Irina-Kira [14]

Answer:

(-4,3)=x1,y1

m=-2

we have

y-y1=m(x-x1)

y-3=-2(x+4)

y-3=2x+8

2x-y+11=0 is the eqn

4 0
3 years ago
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