Answer:
3
Step-by-step explanation:
3
+
11
⋅
(
8
−
4
)
÷
(
5
+
6
)
−
4
Subtract 4 from 8
.
3
+
11
⋅
4
÷
(
5
+
6
)
−
4
Multiply 11 by 4
.
3
+
44
÷
(
5
+
6
)
−
4
Find the common denominator.
Add 5 and 6
.
3
+
44
÷
11
−
4
Write 3 as a fraction with denominator 1
.
3/
1
+
44
÷
11
−
4
Multiply 3/
1 by 11/
11
.
3/
1
⋅
11
/11
+
44
÷
11
−
4
Multiply 3/
1 and 11
/11
.
3
⋅
11
/11
+
44
÷
11
−
4
Write −
4 as a fraction with denominator 1
.
3
⋅
11
/11
+
44
÷
11
+ −
4
/1
Multiply −
4
/1 by 11
/11
.
3
⋅
11
/11
+
44
÷
11
+
−
4
/1 ⋅
11
/11
Multiply
−
4
/1 and 11
/11
.
3
⋅
11
/11
+
44
÷
11
+ −
4
⋅
11
/11
Combine the numerators over the common denominator.
3
⋅
11
+
44
−
4
⋅
11
/11
Simplify each term.
Multiply 3 by 11
.
33
+
44
−
44
⋅
11/
11
Multiply −
4 by 11
.
33
+
44
−
44
/11
Simplify the expression.
Add 33 and 44
.
77
−
44/
11
Subtract 44 from 77
.
33
/11
Divide 33 by 11
.
3
Answer:
182
Step-by-step explanation:
Sum = a(r^n -1) ÷ r - 1
1(-3^6 - 1) ÷ -3 -1
= 182
r = t2 ÷ t1 * since they stated that it is geometric
We could write the fractions as decimals.
The answer is
.004 or 4/1000.
Answer:
The Proof and Explanation for
Part C ,
Qs 9 and
Qs 10 are below.
Step-by-step explanation:
PART C .
Given:
AD || BC ,
To Prove:
ΔAED ≅ ΔCEB
Proof:
Statement Reason
1. AD || BC 1. Given
2. ∠A ≅ ∠C 2. Alternate Angles Theorem as AD || BC
3. ∠AED ≅ ∠CEB 3. Vertical Opposite Angle Theorem.
4. AE ≅ EC 4. Given
5. ΔAED ≅ ΔCEB 5. By A-S-A congruence test....Proved
Qs 9)
Given:
AB ≅ BC ,
∠ABD ≅ ∠CBD
To Prove:
∠A ≅ ∠C
Proof:
Statement Reason
1. ∠ABD ≅ ∠CBD 1. Given
2. AB ≅ CB 2. Given
3. BD ≅ BD 3. Reflexive Property
4. ΔABD ≅ ΔCBD 4. By S-A-S congruence test
5. ∠A ≅ ∠C 5. Corresponding parts of congruent Triangles Proved.
Qs 10)
Given:
∠MCI ≅ ∠AIC
MC ≅ AI
To Prove:
ΔMCI ≅ ΔAIC
Proof:
Statement Reason
1. ∠MCI ≅ ∠AIC 1. Given
2. MC ≅ AI 2. Given
3. CI ≅ CI 3. Reflexive Property
4. ΔMCI ≅ ΔAIC 4. By S-A-S congruence test
