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Elis [28]
3 years ago
13

Factor the expression below using the greatest common factor. 6p(cubed)-2p(cubed)-8p

Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer:

ggykuhhuygkijhkuhkjhjh

Step-by-step explanation:

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Explain how you would graph the line containing a slope of-1/5 that goes through the point (1,-4)​
madam [21]

Answer:

y= -1/5x + 1/5

Step-by-step explanation:

y- y1 = m(x - x1)

Slope m=-1/5

(1, -4)

1 = y1

-4 = x1

y- 1 = -1/5(x-(-4))

y-1 = -1/5(x+4)

y-1= -1/5(x)+ -1/5(4)

y-1 = -1/5x + -4/5

add one to both sides

y= -1/5x + -4/5 + 1

y = -1/5x + 1/5

8 0
4 years ago
ALL of the Students at Beach Middle School voted for a trip to the zoo or the aquarium.
QveST [7]

Answer:

160

Step-by-step explanation:

If there were only 2 options, all the people who didn't pick one chose the other one.

So if 25% of the people voted for the aquarium the remaing 75% voted for the zoo.

Since three times as many people voted for the zoo, we can see that 120/3=40, so 40 people chose the aquarium.

To find the total number of students, we add 120 and 40 to get <u>160</u>

3 0
2 years ago
Divide to find the quotient. Please help ! Just tell me what write in boxes
vichka [17]

Answer: 8 r 2

Step-by-step explanation:

The closest thing that goes into 26 is 24, which goes into 3 8 times. Subtract 24 from 26, and you are left with 2. The 2 you are left with will be your remainder.

8 0
3 years ago
Read 2 more answers
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
What is the value of log^416
crimeas [40]

Answer:

log 4

Step-by-step explanation:

Log 4 is the answer

6 0
4 years ago
Read 2 more answers
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