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castortr0y [4]
3 years ago
6

Assume that nextWord is a String variable that has been given a String value consisting entirely of letters. Write some Java cod

e that outputs the message "First half of the alphabet" , provided nextWord precedes "N" in alphabetic ordering. IfnextWord does not precede "N" in alphabetic ordering, the code should output"Second half of the alphabet" . (Note that "N"uses double quotes to produce aString value, as opposed to using single quotes to produce achar value.) '
Computers and Technology
1 answer:
wel3 years ago
8 0

Answer:

The code example is given below with explanation in c++ language.

Explanation:

Comments will explain what's going on in the code. Below code is already compiled and tested.

#include <time.h>

#include <iostream>

#include <sstream>

using namespace std;

int main(void)

{

//defining start and end time variable

// which will be used to break the infinte loop

   time_t endwait;

   time_t start = time(NULL);

   time_t seconds = 3; // end loop after this time has elapsed

cout<<"Input your number :";

long userNum;

cin>> userNum;

// initializing end time by adding seconds with start time

   endwait = start + seconds;

   // defining outputString which will concatenate all the  

   // divisible numbers in loop

string outputString="";

// bool isCompleted will use to check whether our  

// loop breaks successfully or time is expired.

bool isCompleted=true;

// iterate loop until it comes to 1. as in loop

// the program already displayed the 1 value.

   while (userNum>1)

   {  

  // checking start and end time comparison to  

  // break the infinite loop after some seconds

    if(start >= endwait){

     cout<< "Program end never reached.";

     isCompleted=false;

     break;

 }

 

    userNum=userNum/2;

   // defining stringstream to convert from long to string

    stringstream longToString;

    longToString<<userNum;

  // concatenating all the values

    outputString = outputString + longToString.str()+" ";

   // re initializing the start time with current time.

       start = time(NULL);

   }

   

  // check if while loop breaks successfully then print the

   // series of numbers here.

   if(isCompleted) {

    cout << outputString;

}

   return 0;

}

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Write a program that reads a series of strings andprints only those strings beginning with the letter "b."
coldgirl [10]

Answer:

#include <iostream>

using namespace std;

int main()

{

char str[100][20];

int n;

cout<<"Strings you want to enter"<<endl;

cin>>n;

cout<<"enter n strings"<<endl;

for(int i=0;i<n;i++)

cin>>str[i];

for(int i=0;i<n;i++)

{

if((int)str[i][0]==98) //ascii value b is 98

cout<<str[i]<<endl;

}

return 0;

}

Explanation:

The above written code is for printing the strings which starts with the letter b.

To check if the string starts with a letter b we are checking the ascii value 98 which corresponds to b and then printing those strings.

6 0
3 years ago
Which expression correctly determines that String s1 comes before String s2 in lexicographical order
Assoli18 [71]

Options :

A.) s1 < s2

B.) s1 <= s2

C.) s1.compareTo(s2) == −1

D.) s2.compareTo(s1) < 0

E.) s1.compareTo(s2) < 0

Answer: E.) s1.compareTo(s2) < 0

Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.

If first string = s1 ; second string = s2

To compare s1 with s2, the format is ;

s1.compareTo(s2) ;

If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.

If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.

If both are s1 and s2 are the same, the output will be 0.

8 0
3 years ago
Which options can you choose to determine the width and height of data or cells in a spreadsheet? You can choose the or rulers t
Tju [1.3M]

Answer :

Double click on boarder width an height will automatically adjust.

Manual procedure are following:

1.Open desire file of spreadsheet

2. Click on home tab in cell group and then click format.

3. Under cell size click on default width.

4. In standered column width box type new measurements and then click OK.

4 0
3 years ago
With the _____, users do not need to be concerned with new software versions and compatibility problems because the application
Simora [160]
The answer is push with the push 
7 0
3 years ago
Read 2 more answers
Can you please help look at the picture i will give you a. brainliest and 10 points​
AveGali [126]

Answer:

The last one

Explanation:

6 0
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