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OLga [1]
4 years ago
10

Which of the following was not important in the development of the internet?

Computers and Technology
2 answers:
lesantik [10]4 years ago
8 0
D. Rise of NASA.Hope I helped.
Nataly [62]4 years ago
5 0
The answer would be D
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Write long answer to the following question. a. Define microcomputer. Explain the types of microcomputers in detail.​
Dafna11 [192]

Answer:

Microcomputer, an electronic device with a microprocessor as its central processing unit.

Explanation:

There are three types of microprocessors namely, CISC, RISC, and EPIC. ... A microprocessor is basically the brain of the computer. We can also call it simply a processor or CPU. Furthermore, a microprocessor is basically a computer processor that is mounted on a single IC (Integrated Circuit).

Uses transistors for more registers: Transistors are used for storing the complex instr...

RISC: CISC

Fewer registers are used: It requires more number of registers

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3 years ago
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What are language standards? At this point in your study of programming, what do they mean to
garri49 [273]
In computing, a programming language specification (or standard or definition) is a documentation artifact that defines a programming language so that users and implementors can agree on what programs in that language mean.
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4 years ago
Describe two ways that using frames helps move data along a network
Helen [10]
Frames move bigger amounts of data through the network thus making it faster.
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3 years ago
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4 years ago
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Write a function to sum the following series:
Phoenix [80]

Answer:

<u>C program to find the sum of the series( 1/2 + 2/3 + ... + i/i+1)</u>

#include <stdio.h>

double m(int i);//function declaration  

//driver function

int main() {

int i;

printf("Enter number of item in the series-\n");//Taking input from user

scanf("%d",&i);

double a= m(i);//Calling function

printf("sum=%lf",a);

return 0;

}

double m(int i)//Defining function

{

double j,k;

double sum=0;

for(j=1;j<i+1;j++)//Loop for the sum

{

k=j+1;

sum=sum+(j/k);

}

return sum;

}

<u>Output:</u>

Enter number of item in the series-5

sum=3.550000

5 0
3 years ago
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