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Archy [21]
3 years ago
7

In parallelogram ABCD, AE=x^2-6 and CE=5x what is the value of x ? What is AC?

Mathematics
1 answer:
lutik1710 [3]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, hence

AE = EC, that is

x² - 6 = 5x ( subtract 5x from both sides )

x² - 5x - 6 = 0 ← in standard form

(x - 6)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 6 = 0 ⇒ x = 6

x + 1 = 0 ⇒ x = - 5

However x > 0 ⇒ x = 6

AC = x² - 6 + 5x = 6² - 6 + 5(6) = 36 - 6 + 30 = 60

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Answer:

x= 2

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Step-by-step explanation:

y = 6x + 8

y = –4x – 2

y = 4 (6x + 8 )

y = 6 (–4x – 2)

y = 24x + 32

y = –24 -12

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y = 20

input that back into the equation to find x

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20 - 8 = 6x

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Write the slope-intercept form of the line that passes through (-10,17) and (5,-4)
luda_lava [24]

Answer:

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Step-by-step explanation:

To find the slope, we need to use the formula

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m =(-4-17)/(5- -10)

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The slope is 7/5.


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