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3 years ago

What is the area of a rectangle that is 4 x 4 1/2?

1 answer:

6 0

The area of the rectangle is 18 , I didn't understand the equation fully so I did (4*4.5=18) because (1/2=.5) .

Hope this helps

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OnIy girIs +18 can h0in here for $£X dbp-efnh-cec

Yuliya22 [10]

What the hell

Why are u doing this here

4 0

3 years ago

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Marie purchased a 29.00 gift. She uses a coupon that offers 30 percent. How much will she spend on the gift after the coupon?

asambeis [7]

Answer:

$20.30

Step-by-step explanation:

The usual price of the gift is $29.00

Marie will get 30% DISCOUNT on this price if she uses her coupon. So, the final price would be 30% less than $29.00

First, we need to find 30% of $29.00. Then we need to subtract that from original price (29).

Convert percentage to decimal first:

30% = 30/100 = 0.3

Now multiply this with 29 to get:

0.3 * 29 = $8.70

We subtract this from original price to get DISCOUNTED PRICE:

$29.00 - $8.70 = $20.30

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4 years ago

Anwser the question for brainlist

docker41 [41]

Answer:

Step-by-step explanation:

4 0

3 years ago

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2. A fish tank is shaped like a rectangular prism. 1 2 square feet. The area of the base of the fish tank is 6 The height of the

Assoli18 [71]

Answer:

A. Makes the most sense. If you are using multiplication you'd get 18 1/16

Step-by-step explanation:

4 0

2 years ago

Find the slope of the curve below at the given points. Sketch the curve along with its tangents at these points. R = sin 2 theta

mr Goodwill [35]

Answer:

-1 

Step-by-step explanation:

Given that:

r = sin 2θ , θ = ± π/4 , ± 3π/4

Recall that:

x = r cosθ

y = r sinθ

The differential of y with respect to x

$\dfrac{dy}{dx} = \dfrac{\dfrac{dy}{d \theta}}{\dfrac{dx}{d \theta}}$

$\dfrac{dy}{dx} =\dfrac{\dfrac{dy}{d \theta}}{\dfrac{dx}{d \theta}} = \dfrac{ r cos \theta + sin \theta* \dfrac{dr}{d \theta} } {\dfrac{dr}{d \theta} *cos \theta- sin \theta \ r}$

at θ = π/4 , r = sin π/2

r = 1

$\dfrac{dy}{dx} = \dfrac{ r cos \theta + 2 cos (2 \theta)*sin \ \theta } {2 \ cos (2 \theta) *cos \theta- sin 2 \theta * sin \theta}$

where;

θ = π/4

$\dfrac{dy}{dx} = \dfrac{ 1 \times cos (\dfrac{\pi}{4}) + 2 cos (\dfrac{\pi}{2})*sin (\dfrac{\pi}{4}) } {2 \ cos (\dfrac{\pi}{2})*cos (\dfrac{\pi}{4})- sin (\dfrac{\pi}{2}) * sin (\dfrac{\pi}{4})}$

$\dfrac{dy}{dx} = \dfrac{\dfrac{1}{\sqrt{2}}+0 }{0-1 * \dfrac{1}{\sqrt{2}}}$

$\dfrac{dy}{dx} = \dfrac{\dfrac{1}{\sqrt{2}} }{- \dfrac{1}{\sqrt{2}}}$

$\mathbf{\dfrac{dy}{dx} =-1}$

slope of the curve (dy/dx) at theta(θ) = pi/4 is -1

7 0

3 years ago