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Mama L [17]
3 years ago
12

Two positive numbers are in the ratio 2:3.

Mathematics
1 answer:
blondinia [14]3 years ago
4 0

Answer:

60 and 90

Step-by-step explanation:

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Please help #6 asap
EleoNora [17]

Answer:

c is the answer for number 6 and

Step-by-step explanation:

and b is the answer for number 7

7 0
3 years ago
Read 2 more answers
What step isolates the variable in the equaiton x/2 = 16? <br> (Will mark yo brainliest)
VashaNatasha [74]

Answer:

Multiply 2 i think!

Step-by-step explanation:

Hope this helped!

3 0
3 years ago
Identify the initial value and rate of change for the graph shown. A coordinate plane graph is shown. A line is graphed that pas
egoroff_w [7]
Y int at (0,4).....thru points (4,1)
slope = (1 - 4) / (4 - 0) = -3/4
initial value 4, slope(rate of change) is -3/4 <==
=======================
y = 22,000x + 40,000
=======================
y = 12x + 48
slope(rate of change) = 12
=======================
(1,10)(2,8)
slope = (8-10) / (2-1) = -2/1 = -2

y = mx + b
8 = -2(2) + b
8 = -4 + b
8 + 4 = b
12 = b

slope(rate of change) = -2
initial value = 12
I am not getting any of ur answer choices ...
======================
y = x + 6
initial value = 6
8 0
3 years ago
Please help me on this!
Shtirlitz [24]

Answer:

(a.) B: 8,000

(b.) C: 800

(c.) A. 10 times

Step-by-step explanation:

8762 has 3 digits after the 8. 8,000 has 3 digits after the 8

851 has 2 digits after the 8. 800 has 2 digits after the 8.

8,000 ÷ 800 = 10

Another way to do it is: 8000 has 3 zeros and 800 has 2 zeros.

3 - 2 = 1. 10 has 1 zero.

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

5 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
3 years ago
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