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gizmo_the_mogwai [7]
3 years ago
12

I Really need help with this!

Mathematics
2 answers:
Aneli [31]3 years ago
7 0
We'll have to assume that these triangles are similar.
If that's the case, then the following ratio is true:

38            55
------- = --------
 15.2         x

Then 38x = 836, and x = 836/38 = 22 (answer)
Scrat [10]3 years ago
5 0
Where the heck did x come from!
You might be interested in
Help help help help please
vodomira [7]

Answer:

x<-3

Step-by-step explanation:

-7x+6/3 >9

-7x+6 >27

-7x>27-6

-7x>21

-x>3

x<-3

7 0
2 years ago
Fill the blank bellow.....
Lemur [1.5K]

slope = (y2-y1)/(x2-x1)

the first slope is 0 (horizontal line)

second slope is undefined (vertical line)

3 0
3 years ago
1.. A train travels at a speed of 58 km/hr. If it goes from one station to the next in 1.6 hours, how far has it traveled?
wel

Answer:

92.8 km

Step-by-step explanation:

s=d/t

58=d/1.6

58*1.6=d

92.8=d

7 0
3 years ago
Please help me. if you can help me answer multiple questions only 3. offering 30 points for it
lubasha [3.4K]

Answer:

(-9, -5)

Step-by-step explanation:

Ok, so when you move an image to the right, you are moving along the x-axis, and when you move up, you are moving up the y-axis. So if the altered image is (x,y) and the values are (-5, -1), you reverse what has been done to the image. In this case, since we moved to the right 4 units, we know that means we added 4 to x, so we subtract 4 to get -9. And then, for the y-value, because we added 4, we do the opposite, and subtract 4 to get -5. So the pre-image should be (-9, -5)

7 0
3 years ago
Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0
3 years ago
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