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gizmo_the_mogwai [7]
3 years ago
12

I Really need help with this!

Mathematics
2 answers:
Aneli [31]3 years ago
7 0
We'll have to assume that these triangles are similar.
If that's the case, then the following ratio is true:

38            55
------- = --------
 15.2         x

Then 38x = 836, and x = 836/38 = 22 (answer)
Scrat [10]3 years ago
5 0
Where the heck did x come from!
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What is the problem of this solving?!
nika2105 [10]
     This question can be solved primarily by L'Hospital Rule and the Product Rule.

y= \lim_{x \to 0}  \frac{x^2cos(x)-sin^2(x)}{x^4}
 
     I) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[2xcos(x)-x^2sin(x)]-2sin(x)cos(x)}{4x^3}
 
     II) Product Rule and L'Hospital Rule:

y= \lim_{x \to 0} \frac{[-2xsin(x)+2cos(x)]-[2xsin(x)+x^2cos(x)]-[2cos^2(x)-2sin^2(x)]}{12x^2} \\ y= \lim_{x \to 0} \frac{2cos(x)-4xsin(x)-x^2cos(x)-2cos^2(x)+2sin^2(x)}{12x^2}
 
     III) Product Rule and L'Hospital Rule:

]y= \alpha + \beta \\ \\ \alpha =\lim_{x \to 0} \frac{-2sin(x)-[4sin(x)+4xcos(x)]-[2xcos(x)-x^2sin(x)]}{24x} \\ \beta = \lim_{x \to 0} \frac{4sin(x)cos(x)+4sin(x)cos(x)}{24x} \\  \\ y = \lim_{x \to 0} \frac{-6sin(x)-4xcos(x)-2xcos(x)+x^2sin(x)+8sin(x)cos(x)}{24x}
 
     IV) Product Rule and L'Hospital Rule:

y = \phi + \varphi \\  \\ \phi = \lim_{x \to 0}  \frac{-6cos(x)-[-4xsin(x)+4cos(x)]-[2cos(x)-2xsin(x)]}{24x}  \\ \varphi = \lim_{x \to 0}  \frac{[2xsin(x)+x^2cos(x)]+[8cos^2(x)-8sin(x)]}{24x}
 
     V) Using the Definition of Limit:

y= \frac{-6*1-4*1-2*1+8*1^2}{24}  \\ y= \frac{-4}{24}  \\ \boxed {y= \frac{-1}{6} }
3 0
3 years ago
A number from 1 to 10 is written down. What is the likelihood that the number is even?
dezoksy [38]
D) <span>equally likely as unlikely because there is a 5/10 chance to get an odd and an even making it a 50% chance at each</span>
6 0
4 years ago
What is the area of the figure in the picture above?
jek_recluse [69]
The square area is 6*6=36
For the two triangles, the area is base*height/2 = 6*3 = 18.
So the total area is 18+36+18=72
4 0
4 years ago
keith made $306.00 for 18 hours of work at the same rate how many hours would he have to work to make $204.00
Mice21 [21]
306 / 18 = 17
So he's on $17 / hour

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4 0
3 years ago
6000 whole number multiplied by a power of ten
Firdavs [7]
6000=6×10^3 (3 zeros)
8 0
3 years ago
Read 2 more answers
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