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mixas84 [53]
3 years ago
6

Which explains whether or not the function represents a direct variation?

Mathematics
2 answers:
Setler79 [48]3 years ago
8 0

This function represents a direct variation because it passes through the origin and has a constant rate of change of $5 per hour.

Bas_tet [7]3 years ago
8 0

Solution:

Meaning of Direct Variation:

Two quantity are said to vary directly if changes in two quantity are same i.e if one changes by p times other also changes by p times keeping the ratio same or equivalent.

Two variables x and y are said to be vary directly if it can be written as ,

 →x= k y.

So, among all the statements , Option A : Represents a function of Direct variation because it passes through the origin and has a constant rate of change of $5 per hour.→→→Can be Written as , y= 5 x if it is a linear function passing through origin. That is \frac{y}{x} {\text{is always }=5

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luda_lava [24]

Answer:

Constant of proportionality should be 48.

Step-by-step explanation:

Given that a small pie factory needs to ship 360 pies a day to stay profitable. 180 pies are baked every 3 hours. Of the baked pies, 20% go directly to freezer storage and 80% are loaded on a truck for delivery.

Now we need to find about what is the constant of proportionality for the number of pies baked and loaded on a truck for delivery.

Number of baked pies = 180

Number of pies loaded on truck for delivery = 80% of baked pies

= 0.80(180)= 144 in 3 hours.

So number of pies loaded per hour = 144/3= 48

Hence constant of proportionality should be 48.

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Answer:

6.75 miles per half hour

Step-by-step explanation:

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4 years ago
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Someone help me out please
uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\   (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4.

2 step (A): simplify to obtain the final radical term on one side of the equation.

-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2.

3 step (F): raise both sides of the equation to the power of 2 again.

(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2.

4 step (E): simplify to get a quadratic equation.

4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0.

5 step (D): use the quadratic formula to find the values of x.

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6 step (C): apply the zero product rule.

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Additional 7 step: check these solutions, substituting into the initial equation.

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Answer:

I think is D

Step-by-step explanation:

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3x+2(5x-3)=7

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