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jek_recluse [69]
3 years ago
13

Find the product of z1 and z2, where z1 = 2(cos 70° + i sin 70°) and z2 = 4(cos 200° + i sin 200°)

Mathematics
2 answers:
Scilla [17]3 years ago
6 0

Answer: <u>-8i</u>

2(cos 70 + i sin 70) * 4(cos 200 +isin 200)

8 (cos (70+200) + i sin (70+200)     factor a i sin 70 out

8 (cos(270) + i sin (270))

cos 270 is (0,-1)   sin 270 is -1 from the unit circle

cos 270 is 0

8 (0 -i)

<u>-8i</u>

vazorg [7]3 years ago
5 0

Answer:

-8i

Step-by-step explanation:

To multiply numbers is polar form

z1 = r1 ( cos theta 1 + i sin theta 1)

z2 = r2 ( cos theta 2 + i sin theta 2)

z1*z2 = r1*r2 (cos (theta1+theta2) + i sin (theta1+theta2)

z1 = 2(cos 70° + i sin 70°)

z2 = 4(cos 200+ i sin 200)

z1z2 = 2*4 (cos (70+200) + i sin (70+200)

z1z2 = 8 (cos(270) + i sin (270))

       = 8 (0 + i (-1))

       =-8i

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<h2>Step-by-step explanation:</h2>

Given equations;

y₁ = 3x - 8               -------------------(i)

y₂ = 0.5x + 7          --------------------(ii)

To fill the table, substitute the values of x into equations (i) and (ii)

=> At x = 0

y₁ = 3(0) - 8 = -8

y₂ = 0.5(0) + 7 = 7

=> At x = 1

y₁ = 3(1) - 8 = -5

y₂ = 0.5(1) + 7 = 7.5

=> At x = 2

y₁ = 3(2) - 8 = -2

y₂ = 0.5(2) + 7 = 8

=> At x = 3

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=> At x = 4

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y₂ = 0.5(4) + 7 = 9

=> At x = 5

y₁ = 3(5) - 8 = 7

y₂ = 0.5(5) + 7 = 9.5

=> At x = 6

y₁ = 3(6) - 8 = 10

y₂ = 0.5(6) + 7 = 10

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y₂ = 0.5(9) + 7 = 11.5

=> At x = 10

y₁ = 3(10) - 8 = 22

y₂ = 0.5(10) + 7 = 12

The complete table is attached to this response.

(ii) To find the solution of the system of equations using the table, we find the value of x for which y₁ and y₂ are the same.

As shown in the table, that value of <em>x = 6</em>. At this value of x, the values of y₁ and y₂ are both 10.

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