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jek_recluse [69]
4 years ago
13

Find the product of z1 and z2, where z1 = 2(cos 70° + i sin 70°) and z2 = 4(cos 200° + i sin 200°)

Mathematics
2 answers:
Scilla [17]4 years ago
6 0

Answer: <u>-8i</u>

2(cos 70 + i sin 70) * 4(cos 200 +isin 200)

8 (cos (70+200) + i sin (70+200)     factor a i sin 70 out

8 (cos(270) + i sin (270))

cos 270 is (0,-1)   sin 270 is -1 from the unit circle

cos 270 is 0

8 (0 -i)

<u>-8i</u>

vazorg [7]4 years ago
5 0

Answer:

-8i

Step-by-step explanation:

To multiply numbers is polar form

z1 = r1 ( cos theta 1 + i sin theta 1)

z2 = r2 ( cos theta 2 + i sin theta 2)

z1*z2 = r1*r2 (cos (theta1+theta2) + i sin (theta1+theta2)

z1 = 2(cos 70° + i sin 70°)

z2 = 4(cos 200+ i sin 200)

z1z2 = 2*4 (cos (70+200) + i sin (70+200)

z1z2 = 8 (cos(270) + i sin (270))

       = 8 (0 + i (-1))

       =-8i

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2.995 ou 35.940 (?)

Step-by-step explanation:

Não me lembro exatamente como fazer isso, vou mostrar duas maneiras diferentes de resolver isso.

Use a fórmula l = P * r * t

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Para resolver isso, você terá que ... O principal é 29.950, a taxa é 5%, mas se tornará um decimal que é 0,05, e o tempo é 2 Coloque-o na forma de fórmula 29.950 * 0,05 * 2 = 2.995 em interesse

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Espero que funcione!

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