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photoshop1234 [79]
3 years ago
14

1. Expresa cada función cuadrática f en la forma f(x)-yo = p(x – xo) x ϵ R, donde xo , yo , p ϵ R son elegidos apropiadamente. I

ndica las coordenadas
del vértice de la parábola, el mínimo o máximo de la función f, sobre todo R. Traza la gráfica de f.
a) f(x)= 2x2 + 3x -5, ϵ R,
b) f(x)= -3x2 + 7x +9, ϵ R,
c) f(x)= - x +1, ϵ R,


AYUDA LE DARE CORONA PLIS
Mathematics
1 answer:
crimeas [40]3 years ago
7 0

Answer:

Step-by-step explanation:

1. Express each quadratic function f in the form f (x) -yo = p (x - xo) x ϵ R, where xo, i, p ϵ R are appropriately chosen. Indicate the coordinates

of the vertex of the parabola, the minimum or maximum of the function f, especially R. Draw the graph of f.

a) f (x) = 2x2 + 3x -5, ϵ R,

b) f (x) = -3x2 + 7x +9, ϵ R,

c) f (x) = - x +1, ϵ R,

HELP YOU GIVE YOU CORONA PLIS

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if you're currently making $6.75 per hour and you were offered a new job that pays $7.47 per hour, what will be your percent of
worty [1.4K]

Answer:

10.67% increase

Step-by-step explanation:

We can find percent increase with (difference/original) x 100

7.47 - 6.75

= 0.72 (difference)

(0.72/6.75) x 100

= 10.67% increase

5 0
3 years ago
Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =
marta [7]

Answer:

The integral for the arc of length is:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx

By using Simpon’s rule we get: 1.5355453

And using technology we get:  2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx

We need the derivative of the function:

f'(x)=\frac{1}{x}

And we need it squared:

[f'(x)]^2=\frac{1}{x^2}

Then the integral is:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx

Now, the Simposn’s rule with n=4 is:

\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)

In this problem:

a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}

So, the Simposn’s rule formula becomes:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)

Then simplifying a bit:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)

Then we just do those computations and we finally get the approximation via Simposn's rule:

\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%

8 0
3 years ago
А
Tpy6a [65]

Answer:

angle abc=125°

.......................

6 0
3 years ago
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The table shows the advertised cost and total cost after sales tax is included to two items purchased.
Softa [21]

Answer:

t = 0.05a

t = 1.05a

Step-by-step explanation:

6 0
2 years ago
Compute each sum or difference<br> 9/10+7/9<br> 1/2-3/11<br> 2/5-1/15
Galina-37 [17]
1. 9/10 + 7/9 = 81/90 + 70/90 = 151/90 = 1 61/90
2. 1/2-3/11 = 11/22-6/22 = 5/22
3. 2/5-1/15 = 6/15-1/15 = 5/15 =1/3
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3 years ago
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