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eduard
3 years ago
6

Please help Show workings Pleasssssseeeeee

Mathematics
1 answer:
Ad libitum [116K]3 years ago
7 0
Just set them equal to each other
2x-2= x+3

2x-5=x
-5= -x
X=5

Hope it helps
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3x+4y=10 solve for y
Sever21 [200]

Answer:

y=5/2 - 3x/4

Step-by-step explanation:

7 0
3 years ago
Write the computer program for;urgent​
AlladinOne [14]

ANSWER:

#include <stdio.h>

#define PAYRATE 10 //basic pay rate per hour

#define OVERTIME 15 //in excess of 40 hours a week

int NetPay(int hours);

int main()

{

int userWeeklyHours;

printf("Please enter your total weekly working hours: \n");

scanf("%d", &userWeeklyHours);// get the user weekly hours

NetPay(userWeeklyHours);

return 0;

}

int NetPay(int hours)// implementing the function to calculate total pay, total taxes, and net pay

{

int firstRate, secondRate, restOfRate, secondAmount, rest, payAfterTax, payedBeforeTax, overHours;

if (hours > 40)

{

overHours = hours - 40;

payedBeforeTax = (40 * PAYRATE) + (overHours * OVERTIME);

}

else

payedBeforeTax = hours * PAYRATE;//defining the user first paycheck before taxes

if (payedBeforeTax <= 300)//paying only first rate case

{

firstRate = payedBeforeTax*0.15;

payAfterTax =payedBeforeTax - firstRate;

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate, payAfterTax);

}

else if (payedBeforeTax > 300 && payedBeforeTax <= 450)//paying first and second rate

{

secondAmount = payedBeforeTax - 300;

firstRate = (payedBeforeTax - secondAmount) * 0.15;

secondRate = secondAmount * 0.20;

payAfterTax = payedBeforeTax - (firstRate + secondRate);

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate + secondRate, payAfterTax);

}

else if (payedBeforeTax > 450)// paying all rates

{

rest = payedBeforeTax - 450;

secondAmount = (payedBeforeTax - 300) - rest;

firstRate = (payedBeforeTax - (rest + secondAmount)) * 0.15;

secondRate = secondAmount * 0.20;

restOfRate = rest * 0.25;

payAfterTax = payedBeforeTax - (firstRate + secondRate + restOfRate);

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate + secondRate + restOfRate, payAfterTax);

}

return payAfterTax;

}

8 0
3 years ago
Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r
ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                         P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = \frac{\sum X}{n} = 21.88 ounces

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 0.201 ounces

            n = sample of boxes = 12

            \mu = population mean weight

<em>Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.796 < t_1_1 < 1.796) = 0.90  {As the critical value of t at 11 degrees of

                                                  freedom are -1.796 & 1.796 with P = 5%}  

P(-1.796 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.796) = 0.90

P( -1.796 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

P( \bar X-1.796 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.796 \times {\frac{s}{\sqrt{n} } } , \bar X+1.796 \times {\frac{s}{\sqrt{n} } } ]

                                        = [ 21.88-1.796 \times {\frac{0.201}{\sqrt{12} } } , 21.88+1.796 \times {\frac{0.201}{\sqrt{12} } } ]

                                        = [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0
3 years ago
Which graph represents functions ?
Varvara68 [4.7K]
Graph b and d

hope this helps!
8 0
3 years ago
Read 2 more answers
A bakery charges 15 for delivery plus 3 per cupcake. Let C represents the number of cupcakes. Which expression can be used to fi
amid [387]

Answer:

The answer is A.15c+3

Step-by-step explanation:

4 0
2 years ago
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