Find the nth term of this quadratic sequence 4 7 12 19 28
1 answer:
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Answer:
Three-fourths
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
∠QSR≅∠XZY ---> given problem
∠QRS≅∠XYZ ---> given problem
so
△QRS ~ △XYZ ----> by AA Similarity theorem
Remember that, if two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
That means
∠Q≅∠X
∠R≅∠Y
∠S≅∠Z
<em>In the right triangle XYZ</em>
Find the tangent of angle X
---> opposite side angle X divided by adjacent side angle X
substitute the given values
Simplify
Remember that
∠Q≅∠X
so
therefore
---->Three-fourths
Short answer: (-8)^2 + 8 x -8 = 0
Use PEMDAS
"Evaluate the expression" just means solve until you can't simplify anymore. You must solve it in a certain order according to PEMDAS: Parentheses, Exponents, Multiply, Divide, Add, Subtract.
What does the beginning of the expression look like? It is
.
According to PEMDAS, you must solve what is in the parentheses *first*. But, since there is only a number (-8), there is nothing to solve for and you can move on to exponents.
The squared symbol, the little 2, means you have to square what is *inside* the parentheses. = 64, because -8 times itself is 64.
Next comes multiplication. Remember, we are not working from left to right. We must multiply the values on the far right before we do any adding, because multiplication comes *before* addition.
(64) + (8 times -8)
(64) + (-64)
Finally, we can add. In this case, because we are adding a negative number, we are really subtracting. 64 + -64 equals 0.
Use PEMDAS
"Evaluate the expression" just means solve until you can't simplify anymore. You must solve it in a certain order according to PEMDAS: Parentheses, Exponents, Multiply, Divide, Add, Subtract.
What does the beginning of the expression look like? It is
According to PEMDAS, you must solve what is in the parentheses *first*. But, since there is only a number (-8), there is nothing to solve for and you can move on to exponents.
The squared symbol, the little 2, means you have to square what is *inside* the parentheses.
Next comes multiplication. Remember, we are not working from left to right. We must multiply the values on the far right before we do any adding, because multiplication comes *before* addition.
(64) + (8 times -8)
(64) + (-64)
Finally, we can add. In this case, because we are adding a negative number, we are really subtracting. 64 + -64 equals 0.
I did number 6 to give you an idea of what you have to do. First find simplify the top and bottom and reduce!
Hope it helps! Comment if you have any questions!
