Step-by-step explanation:

Hence, option A 85° is the correct answer. 
 
        
                    
             
        
        
        
Answer:
The range of the number of people that are satisfied is option A. 46,968 to 51,912 customers.
Step-by-step explanation:
Hi, to solve this problem you need to calculate the total number of customers that are pleased with the service, based on the 150 people sample.
so:
(72,000 x 103 )÷150 = 49,440
The next step is to calculate the 5% margin of error of that result.
49,440 x 0.05= 2,472
Finally, to obtain the range you need to add and subtract the margin to the total number of customers that are pleased with the service.
49,440-2,472= 46,968
49,440 + 2,472=51,912
So, the range of the number of people that are satisfied is option A. 46,968 to 51,912 customers.
 
        
             
        
        
        
The answer is 8 because you have black and tan pants so 2 pairs and then a green, red, white, and yellow shirt sooooo you have 4 choices of shirts to pair with your pants. So 2•4=8
        
             
        
        
        
The answer si that the first ten odd integers are all even. Maybe this is really a fact but not a conjecture
        
             
        
        
        
Answer:
The 90% confidence interval for the mean test score is between 77.29 and 85.71.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of  . So we have T = 2.064
. So we have T = 2.064
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29
The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.
The 90% confidence interval for the mean test score is between 77.29 and 85.71.