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Nezavi [6.7K]
3 years ago
11

George's page contains twice as many typed words as Bill's page and Bill's page contains 50 fewer words than Charlie's page. If

each person can type 60 words per minute, after one minute, the difference between twice the number of words on Bill's page and the number of words on Charlie's page is 210. How many words did Bill's page contain initially?
Bill's page initially contained ___ words.
Mathematics
1 answer:
seropon [69]3 years ago
6 0
The answer to this question is:

Bill's page initially contained 260 words.
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HELP FOR BRAINLIEST<br> 55 POINTS !!!
Darya [45]

Step-by-step explanation:

m \angle DBE =  \frac{1}{2}  \{m (arc\: AC) + m (arc\: DE)  \} \\  \\  =  \frac{1}{2} (130 \degree + 40 \degree) \\  \\  =  \frac{1}{2}  \times 170 \degree \\  \\    \huge \purple{ \boxed{\therefore  m \angle DBE = 85\degree}}

Hence, option A 85° is the correct answer.

5 0
3 years ago
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A survey about phone service has a margin of error of 5%. Out of 150 people surveyed, 103 said that they were pleased with their
lapo4ka [179]

Answer:

The range of the number of people that are satisfied is option A. 46,968 to 51,912 customers.

Step-by-step explanation:

Hi, to solve this problem you need to calculate the total number of customers that are pleased with the service, based on the 150 people sample.

so:

(72,000 x 103 )÷150 = 49,440

The next step is to calculate the 5% margin of error of that result.

49,440 x 0.05= 2,472

Finally, to obtain the range you need to add and subtract the margin to the total number of customers that are pleased with the service.

49,440-2,472= 46,968

49,440 + 2,472=51,912

So, the range of the number of people that are satisfied is option A. 46,968 to 51,912 customers.

8 0
3 years ago
A local middle school adopted a policy for school uniforms. Students can wear black pants or tan pants. They can wear a yellow s
ValentinkaMS [17]
The answer is 8 because you have black and tan pants so 2 pairs and then a green, red, white, and yellow shirt sooooo you have 4 choices of shirts to pair with your pants. So 2•4=8
5 0
3 years ago
What conjecture can you make about the sum of the first 10 odd integers
saul85 [17]
The answer si that the first ten odd integers are all even. Maybe this is really a fact but not a conjecture
3 0
3 years ago
Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

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3 years ago
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