May be there is an operator missing in the first function, h(x). I will solve this in two ways, 1) as if the h(x) = 5x and 2) as if h(x) = 5 + x
1) If h(x) = 5x and k(x) = 1/x
Then (k o h) (x) = k ( h(x) ) = k(5x) = 1/(5x)
2) If h(x) = 5 + x and k (x) = 1/x
Then (k o h)(x) =k ( h(x) ) = k (5+x) = 1 / [5 + x]
Answer:
=4/5(N+7)N
Step-by-Step Explanation:
We move all terms to the left:
-(4/5(N+7)N)=0
Domain of the equation: 5(N+7)N)!=0
N∈R
We multiply all the terms by the denominator
-(4=0
We add all the numbers together, and all the variables
=0
N=0/1
N=0
Its 56 I DID this you could only multiple the straight sides