Ask question

Ask question

All categories

3 years ago

11

Antonio buys a bag of food for his cat, Tiger. The bag weighs 3.2 pounds and costs $3.84. How much does Tiger's cat food cost pe

r pound?

1 answer:

MAXImum [283]3 years ago

5 0

Answer:

$1.20 per pound

Step-by-step explanation:

Take the Cost, or $3.84 divided by the weight, or 3.2 pounds, and you'll get 1.2, or $1.20 per pound.

You might be interested in

Which system of equations below will have infinite solutions?

ipn [44]

Answer:

All

Step-by-step explanation:

Because there are no equations for them so for all we know they all could have infinite solutions.

5 0

2 years ago

Y is proportional

Scorpion4ik [409]

Answer:

B :) (im sure btw)

Step-by-step explanation:

5 0

3 years ago

Wangari plants trees at a constant rate of 12 trees every 3 hours. Write a equation that relates p, the number of trees Wangari

stealth61 [152]

Answer:

4h=p

Step-by-step explanation:

This is the answer because if both the number of trees and hours is divided by three, you get 4 trees per hour. So it's 4 times (h) equals total amount of trees planted.

4 0

3 years ago

Read 2 more answers

Mazyrski [523]

Answer:

$23\sqrt{3}\ un^2$

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

$A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\$

2. Note that

$A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2$

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

$A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2$

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

7 0

3 years ago

9times 2/3 and than in simplest form

Alex17521 [72]

18/3 then it will be 6

7 0

3 years ago