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kotykmax [81]
3 years ago
8

How is theis function transformed from the parent function? F(x) = [1/x-5] -1

Mathematics
1 answer:
Lina20 [59]3 years ago
7 0
-6 that’s the answer hope this helps

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Carrie had $1.00. She spent $0.64 on a present for her teacher. What percent of money did she spend?
tangare [24]
The answer is 64% 64/100 is 64%
4 0
3 years ago
Read 2 more answers
A well know Statistical Institution claims that the average College tuition for a law degree costs at least thirty five thousand
kirill [66]

Step-by-step explanation:

Below are the null and alternative Hypothesis,

Null Hypothesis, H0: μ = 35000

Alternative Hypothesis, Ha: μ < 35000

Test statistic,

z = (xbar - mu)/(sigma/sqrt(n))

z = (33450 - 35000)/(5978/sqrt(50))

z = -1.83

P-value Approach

P-value = 0.0336

As P-value >= 0.02, fail to reject null hypothesis.

There is not sufficient evidence to conclude that the average College tuition for a law degree costs at least thirty five thousand dollars.

4 0
3 years ago
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
When is the magnetic field the strongest?
kodGreya [7K]
When it's by the magnetic poles
6 0
3 years ago
Read 2 more answers
X^3 -x-340<br><br>please explain how you got it <br><br>please help me​
Makovka662 [10]

Answer: x = 18.439

Step-by-step explanation:

x³-x = 340

x² = 340

x = √340 = 18.439

8 0
3 years ago
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