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3 years ago

-x^2+2x-1 factor and please show work

Mathematics

1 answer:

torisob [31]3 years ago

4 0

x = 1

$-x^{2} +2x-1=0\\-(x-1)^{2} \\x=1$

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At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

7 0

4 years ago

Determine the function which corresponds to the given graph <br> the asymptote is x= -1

MissTica

Answer:

Can't answer

Step-by-step explanation:

6 0

3 years ago

Adam makes $632 gross income per week and has claimed four allowances. According to the table below, what is Adam’s net income a

Paul [167]

The answer is B(533)

7 0

3 years ago

Read 2 more answers

What is the solution of 3+x-2/x-3<_4

VikaD [51]

Step-by-step explanation:

3+x-2/x-3<_4

cross multiply

3+x-2<_4(x-3)

3+x-2<_4x-12

1+x<_4x-12

collect like terms

1+12<_4x-x

13<_3x

divide both side by 3

13/3<_×

6.5<_x

3 0

3 years ago

Each week morning sunshine cafe orders coffee packets that costs $2.50 per packet with a 10.00 shipping fee . If morning sunshin

Anni [7]

Answer:

193 packets

Step-by-step explanation:

Each morning they order with a shipping fee of $10 daily.

Considering they order all 7 days of the week, so the total shipping fee for the week would be:

7 * $10 = $70

Their budget for the week is $554, out of which $70 is for shipping for the week, so remaining balance would be:

554 - 70 = $484

This 484 dollars are for coffee packets that cost $2.50 each, so the number of packets would be:

484/2.50 = 193.6

You can't order fractional packets so 193 packets is the max in this budget

7 0

4 years ago