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3 years ago

A square has side length 4 cm. What is the volume

Mathematics

1 answer:

gayaneshka [121]3 years ago

3 0

Answer:

64 cubic cm

Step-by-step explanation:

i think u mean cube btw for volume but if u meant area its 16 cm squared

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ser-zykov [4K]

Answer:

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4 years ago

4^2 + (10 - 2 × 3) ÷ 4 (i just need it to be explain thank you.)

tiny-mole [99]

Answer:

PEMDAS

Step-by-step explanation:

you can solve this, just remember pemdas

5 0

3 years ago

Read 2 more answers

** ANSWER QUICKLY TIMED QUIZ **

maks197457 [2]

$4x^2+32x-28=0\ \ \ |:4\\\\x^2+8x-7=0\ \ \ |+7\\\\x^2+8x=7\\\\x^2+2x\cdot4=7\ \ \ |+4^2\\\\x^2+2x\cdot4+4^2=7+4^2\\\\(x+4)^2=7+16\\\\(x+4)^2=23\\\\Answer:\ B.(x+4)^2=23$

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3 years ago

Mr. Green teaches mathematics and his class recently finished a unit on statistics. The student scores on this unit are: 40 47 5

Harrizon [31]

Answer:

Mean = 64.46, Median = 62 and Mode = Bi-modal (50 and 62)

Range of the data is 55.

Step-by-step explanation:

We are given that Mr. Green teaches mathematics and his class recently finished a unit on statistics.

The student scores on this unit are: 40, 47, 50, 50, 50, 54, 56, 56, 60, 60, 62, 62, 62, 63, 65, 70, 70, 72, 76, 77, 80, 85, 85, 95.

We know that Measures of Central Tendency are: Mean, Median and Mode.

Mean is calculated as;

Mean = $\frac{\sum X}{n}$

where $\sum X$ = Sum of all values in the data

n = Number of observations = 24

So, Mean = $\frac{40+ 47+ 50+ 50+ 50+ 54+ 56+ 56+ 60 +60+ 62+ 62+ 62+ 63+ 65+ 70+ 70+ 72+ 76+ 77+ 80+ 85+ 85+ 95}{24}$

= $\frac{1547}{24}$ = 64.46

So, mean of data si 64.46.

For calculating Median, we have to observe that the number of observations (n) is even or odd, i.e.;

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2})^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

Now here in our data, the number of observations is even, i.e. n = 24.

So, Median = $\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(\frac{24}{2})^{th}\text{ obs.} +(\frac{24}{2}+1)^{th}\text{ obs.} }{2}$

= $\frac{(12)^{th}\text{ obs.} +(13)^{th}\text{ obs.} }{2}$

= $\frac{62 + 62 }{2}$ = $\frac{124}{2}$ = 62

Hence, the median of the data is 62.

A Mode is a value that appears maximum number of times in our data.

In our data, there are two values which appear maximum number of times, i.e. 50 and 62 as these both appear maximum 3 times in the data.

This means our data is Bi-modal with 50 and 62.

The Range is calculated as the difference between the highest and lowest value in the data.

Range = Highest value - Lowest value

= 95 - 40 = 55

Hence, range of the data is 55.

5 0

4 years ago

What are the solutions to the absolute value inequality |x − 70| ≤ 3? Remember, the inequality can be written as −3 ≤ x − 70 ≤ 3

ikadub [295]

Answer:

solutions to the absolute value inequality is $67\leq x\leq 73$

Step-by-step explanation:

To find the solution of x absolute value of |x − 70| ≤ 3 will be written in the form of interval because the given fraction (x-70) is less than and equal to 3.

$-3\leq(x-70)\leq 3$

Now we add 70 on every part of the inequality.

$-3+70\leq (x-70)+70\leq 3+70$

$67\leq x\leq 73$

So the solution to the absolute value inequality is $67\leq x\leq 73$ .

5 0

3 years ago

Read 2 more answers