Answer:
height of the cone = 4.01273885 units
Step-by-step explanation:
Volume of a cone(V) is given by:
....[1]
where,
r is the radius and h is the height of the cone.
As per the statement:
A cone with radius 5 units and ts volume is 105 cubic units
⇒r = 5 units and V = 105 cubic units
Substitute these given values and use 
in [1] we have;
Multiply both sides by 3 we have;
⇒
Divide both sides by 78.5 we have;
or
h = 4.01273885 units
Therefore, the height of the cone is, 4.01273885 units
I think BD is 16 and EC is 9. hope this helps
<h3>Answer is -9</h3>
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Work Shown:
(g°h)(x) is the same as g(h(x))
So, (g°h)(0) = g(h(0))
Effectively h(x) is the input to g(x). Let's first find h(0)
h(x) = x^2+3
h(0) = 0^2+3
h(0) = 3
So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.
Now let's find g(3)
g(x) = -3x
g(3) = -3*3
g(3) = -9
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alternatively, you can plug h(x) algebraically into the g(x) function
g(x) = -3x
g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)
g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3
g( h(x) ) = -3x^2 - 9
Next we can plug in x = 0
g( h(0) ) = -3(0)^2 - 9
g( h(0) ) = -9
we get the same result.
