Due to the u-shaped graph suggested by these data points, this would best be matched with a quadratic function.
Answer:
T1 = 975 / (205 + V) flying with wind
T2 = 975 / (205 - V) flying against wind
T2 = T1 + 2
975 * {1 / (205 - V) - 1 / (205 + V)] = 2
(205 + V + V -205) / (205^2 - V^2) = 2 / 975
V^2 + 975 V - 42025 = 0 rearranging
V = 41.3
Values of flying are 246.3 and 163.7
Check:
T1 = 975 / 246.3 = 3.96 hrs
T2 = 975 / 163.7 = 5.96 hrs
5 x 5 = 25
I hope this helped
To solve this just use the distance formula, which is:
√(x2-x1)^2+(y2-y1)^2
1. plug into formula
√(1-5)^2+(3-3)^2
2. solve
√ (-4)^2+0^2= √16
3. Simplify
B. 4 units
Is greater than 35. hope i helped
