Y = T+3 (i)
T = H+2 (ii)
Y = 2*H (iiii)
T = H+2 therefore H = T-2
Substitute H=T-2 into (iii)
Y=2*H
Y=2*(T-2)
Y=2T-4
Now substitute that Y into (i)
(i) says Y = T+3
2T-4=T+3
2T-T-4=3
T-4=3
T=3+4
T=7
Then from (i) Y=T+3 = 7+3 =10
Y=10
And from (iii) Y=2*H
If Y = 10, then H = 5
V=V of cube- V pyramid= 8^3- 7^2*8/3=512-49*8/3=512-130,67=381.33 cm^3
B=7
3(b-4)+5b=44
3b-12+5b=44
8b=44+12
8b=56
b=7
