All categories

3 years ago

What is the answer to 2x=33

Mathematics

2 answers:

Natasha2012 [34]3 years ago

5 0

Step-by-step explanation:

if you meant something else let me know

I would be happy to help

UkoKoshka [18]3 years ago

3 0

Answer:

2×16.5=33

Step-by-step explanation:

Just divide 33 by 2

You might be interested in

Can someone help please this is due tomorrow

Vikki [24]

1. 4(6+4)
2. 5(1+3)
3. 4(4+5)
4. 4(1+2)
5. 5(2+5)
6. 12(1+3)
7. 24(1+3)
8. 8(5+2)
9. 5(4+10)
10. 4(3+11)
11. 6(6+7)
12. 10(1+6)

6 0

3 years ago

Read 2 more answers

Find the measure of anglexin the figure below:O 95O 55O

jolli1 [7]

Since a triangle equals 180°

We know that x and y angles are the same.

And that 55° + 30° + y = 180°

We just subtract!
sooo
180 - 55 - 33 = 95

So this means y = 95°

And x and y equal the same measurement.
sooo you answer is...

x = 95°

love, the Pineapple <3
\|/
(_)

:D

7 0

4 years ago

Read 2 more answers

Simplify 81 power 5/4 A. 3 B. 243 c. 6,561 d. 59,049

VARVARA [1.3K]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you kno

Ronch [10]

It is a type of active transport because it will require energy to move against the concentration gradient (low to high)
- option A

6 0

3 years ago

Read 2 more answers

Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang

Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - α)% confidence interval for the population standard deviation is:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

The information provided is:

n = 26

s = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611$

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

$=\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3$

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0

3 years ago