If we used “a” tons of grade A and “b” tons of grade B we would get a + b tons of mixture.
Converting to costs we get 36a + 24b = 33(a + b)
36a + 24b = 33a + 33b
36a - 33a = 33b - 24b
3a = 9b
a = 3b
This means the mixture contains 3 times as much of grade A than grade B
The ratio of grade A : grade B = 3 : 1
For example if we mixed 3 tons of A with 1 ton of B we would get 4 tons of mixture
The cost would be 3 x 36 + 1 x 24 = 108 + 24 = $132 for 4 tons = $33 per ton
Answer:
No 4 I think not to sure tho
Answer:
Step-by-step explanation:
From the question we are told that:
Length of pool 
width of pool 
Width of brick-walk way 
Generally the equation for Area of the pool 
is mathematically given by
Generally the equation for Area of the pool with its walkway 
is mathematically given by
Where
Therefore
Generally the equation for pool's walkway 
is mathematically given by
Bonus #1) June 30 is equivalent to the 91st day of April or the 61st day of May.
Hilda's deposit of 4520 earned interest for 91-1 = 90 days.
Hilda's deposit of 580 earned interest for 61-10 = 51 days.
Hilda's deposit of 590 earned interest for 61-23 = 38 days.
Balance = $4520·(1 +.035/365)⁹⁰ + 580·(1 +.035/365)⁵¹ + 590·(1 +.035/365)³⁸
... = $4559.175 +582.843 +592.154
... ≈ $5734.17
Deposits total 4520 +580 +590 = 5690, so interest earned is
... $5734.17 -5690.00 = $44.17
Bonus #2) This problem can be worked the same way, except that withdrawals are subtracted from the final balance.
Owner's deposit of $12,300 earned interest for 91 days.
Owner's withdrawal of $3600 reduced the balance for 53 days.
Owner's withdrawal of $1200 reduced the balance for 10 days.
Balance = $12300·(1 +.035/365)⁹¹ -3600·(1 +.035/365)⁵³ -1200·(1 +.035/365)¹⁰
... = $12,407.795 -3618.342 -1201.151
... ≈ $7588.30
Interest earned = $7588.30 - (12300 -3600 -1200) = $88.30
Answer:
- 3 hours
- 1 hour 45 minutes
- 300 miles
Step-by-step explanation:
1. The trains are moving toward each other at a total speed of 50 +20 = 70 miles per hour. Together, they cover the 210 mile distance in ...
time = distance/speed
time = 210 mi/(70 mi/h) = 3 h
The trains collide after 3 hours.
__
2. The fly is closing with the freight train at a speed of 100 +20 = 120 miles per hour. Together, the fly and the train cover the initial 210 mile distance in ...
(210 mi)/(120 mi/h) = 7/4 h = 1 hour 45 minutes
The fly first meets the oncoming freight train after 1 h 45 min.
__
3. The fly is flying for all three hours before the trains collide, so, at 100 miles per hour, will fly 300 miles.
