A)
3t = 7k/13 - 17
3t + 17 = 7k/13
13*(3t + 17) = 7k
7k = 13*(3t + 17)
7k = 39t + 221
k = (39t + 221) / 7
b)
7k = 4k/3t - 11t
11t = 4k/3t - 7k LCM = 3t
11t = (4k - 21kt) / 3t
11t*3t = (4k - 21kt)
33t² = k(4 - 21t)
33t² /(4 - 21t) = k
k = 33t² /(4 - 21t)
I hope this helps.
Answer:
G
Step-by-step explanation:
It looks like it would be c=4b but 4*7 equals 28 not 30
Answer:
Step-by-step explanation:
The drawing of the garage is a smaller representation of the actual garage. A garage is drawn using a scale of 2 2/3 inch = 6feet. Let us first convert 2 2/3 inch to improper fraction. It becomes 8/3 inch.
Let us determine the unit measurement.
If 6feet = 8/3 inch,
1 foot will be 8/3 ÷ 6 = 8/3×1/6
= 8/18 inches. Therefore
if the actual height is 68 ft , then, the height of the garage on the drawing will be
68 × 8/18 = 272/9 = 30 2/9 inches
Answer:
Step-by-step explanation:
Given that a fair coin is flipped twelve times.
It means the number of possible sequences of heads and tails would be:
2¹² = 4096
We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula
Plug in n = 12 and r = 9
∵ 
∵ 
Thus, the probability will be:
Thus, the probability of the coin landing tails up exactly nine times will be:
